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Question Detail
A flagstaff 17.5 metre high casts a shadow of length 40.25 metre. The height of building, which casts a shadow of length 28.75 metre under similar conditions will be :
 12 metre
 12.5 metre
 13.5 metre
 14 metre
Answer: Option B
Explanation:
Less shadow, Less Height (Direct Proportion)
So, let height of building be x metre
then,
\begin{aligned}
40.25 : 17.5 :: 28.75 : x \\
=> x = \frac{17.5*28.75}{40.25} \\
=> x = 12.5
\end{aligned}
So height of building should be 12.5 metre
1. If 16 toys cost 240, then what do 40 toys cost ?
 Rs. 600
 Rs. 620
 Rs. 640
 Rs. 660
Answer: Option C
Explanation:
Although we can first calculate the cost of one toy and then can multiply it with 40 to get the result.
but we will solve it with chain rule so that we can prepare ourself for other complex problems which we can solve easily by applying this rule.
Let the required cost be Rs. x
More toys means More Cost. (Direct Proportion)
\begin{aligned}
15:40 :: 240:x \\
=> x = \frac{240*40}{15} \\
=> x = 640
\end{aligned}
So 40 toys will cost Rs 640
2. 4 matweavers can weave 4 mats in 4 days. At the same rate, how many mats would be woven by 8 mat weavers in 8 days ?
 12
 14
 16
 18
Answer: Option C
Explanation:
Please always remember, that what exactly we need to calculate before applying chain formula. As in this question we need to find how many mats, RIGHT !
So we will compare everything with "number of mats"
As,
More men, More number of mats (Direct Proportion)
More days, More number of mats (Direct Proportion)
So, it can be solved as,
\begin{aligned}
\begin{bmatrix}Weavers & 4 & 8 \\Days & 4 & 8 \end{bmatrix} :: 4 : x \\
=> x*4*4 = 8*8*4 \\
=> x = 16
\end{aligned}
3. 10 men, working 6 hours a day can complete a work in 18 days. How many hours a day must 15 men work to complete the work in 12 days ?
 4 hours a day
 5 hours a day
 6 hours a day
 7 hours a day
Answer: Option C
Explanation:
More Men, Less Hours {Indirect Proportion}
Less Days, More Hours {Indirect Proportion}
\begin{aligned}
\begin{bmatrix}Men & 15 & 10 \\Days & 12 & 18 \end{bmatrix} :: 6 : x \\
=> x * 15 * 12 = 10 * 18 * 6 \\
=> x = \frac{10*18*6}{15*12} \\
=> x = 6
\end{aligned}
4. If the cost of x metres of wire is d rupees, then what is the cost of y metres of wire at the same rate ?
 xd
 yd
 yd/x
 x/yd
Answer: Option C
5. If the price of 23 toys is 276, then what will the price of 12 toys ?
 144
 148
 156
 186
Answer: Option A
Explanation:
Less toys, Less Price (Direct Proportion)
So, let the price be Rs. x
then,
\begin{aligned}
23:12 :: 276:x
=> x = \frac{276*12}{23} \\
=> x = 144
\end{aligned}
So price of 12 toys will be Rs. 144
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