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Question Detail
Find the least number which leaves a reminder of 3 when divided by 5, 6, 7 and 8, but leaves no reminder when divided by 9 ?
 1683
 1692
 1598
 1458
Answer: Option A
Explanation:
First of all, calculate LCM of 5, 6, 7 and 8 which is 840.
Suppose Number is K
then 840 * K + 3 is divisible by 9.
If K = 1, number = (840 × 1) + 3 = 843 which is not divisible by 9
If K = 2, number = (840 × 2) + 3 = 1683 which is divisible by 9
So 1683 is correct answer.
1. A shepherd had 27 sheep. All but 10 died. How many he left with ?
 10
 15
 17
 27
Answer: Option A
Explanation:
"All but 10 died" means all except 10 died, so he is remained with 10 sheep.
2. In a caravan, in addition to 50 hens, there are 45 goats and 8 camels with some keepers. If the total number of feet be 224 more than the number of heads in the caravan, the number of keepers is
 5
 8
 10
 15
Answer: Option D
Explanation:
Let the number of keepers be x.
Then, total number of feet = 2*50+4*45+4*8+2x
= 2x + 312
Total number of heads = 50+45+8+x = 103 + x
Now, (2x+312) = (103+x)+224
=> x = 15
3. A is three times as old as B. C was twiceas old as A four years ago. In four years' time, A will be 31. What are the present ages of B and C ?
 9, 46
 9, 50
 10, 46
 10, 50
Answer: Option B
Explanation:
As from the question we have,
A = 3B  (i)
c  4 = 2(A+4) (ii)
Also, A + 4 = 31
or A = 314 = 27
Putting A = 27 in (i) we get
B = 9
Putting A = 27 in (ii) we get
C = 50
4. A, B, C and D play a game of cards. A says to B. "If I give you 8 cards, you will have as many as C has and I shall have 3 less than what C has. Also if I take 8 cards from C, I shall have twice as many as D has." If B and D together have 50 cards, how many cards have A got?
 35
 37
 38
 40
Answer: Option D
Explanation:
If we read given question carefully, we get,
B+8 = C (i)
A8 = C3 (ii)
A+6 = 2D (iii)
B+D = 50 (iv)
Putting C = A 5 from (ii) into (i), we have :
B+8 = A5 or AB = 13 (v)
Putting D = 50B from (iv) and (iii), we have :
A+6 = 1002B or A+2B = 94 (vi)
Solving (v) and (vi), we get
B = 27 and A = 40
5. A certain number of horses and an equal number of men are going somewhere. Half of the owners are on their horses' back while the remaining ones are walking along leading their horses. If the number of legs walking on the ground is 70, how many horses are there ?
 8
 10
 12
 14
Answer: Option D
Explanation:
Let number of horses = number of men = x.
Then, number of legs = 4x + 2 x (x/2) = 5x.
So, 5X = 70 or x = 14.
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