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Question Detail
Sushil was thrice as old as Snehal 6 years back. Sushil will be times as old as Snehal 6 years hence. How old is Snehal today
- 12
- 16
- 18
- 24
Answer: Option A
Explanation:
Let Snehals age 6 years back = x.
Then, Sushils age 6 years back = 3x.
(5/3) * (X + 6 + 6) = (3X + 6 + 6)
So 5(x+ 12) = 3(3x+ 12),
so x=6.
Snehal Age = (x+ 6) years = 12 years
1. The total age of A and B is 12 years more than the total age of B and C. C is how many year younger than A
- 11
- 12
- 13
- 14
Answer: Option B
Explanation:
Given that A+B = 12 + B + C
=> A – C = 12 + B – B = 12
=> C is younger than A by 12 years
2. A person's present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. How old is the mother at present
- 38
- 40
- 42
- 44
Answer: Option B
Explanation:
Let the mother's present age be x years.
Then, the person's present age = (2/5 x) years.
=> (2/5 x + 8/2) = 1 (x + 8)
=> 2(2x + 40) = 5(x + 8)
=> x = 40
3. The sum of the present ages of a father and his son is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be
- 15 years
- 18 years
- 20 years
- 22 years
Answer: Option C
Explanation:
Clue : (60 - x) - 6 = 5(x - 6)
4. Sachin was twice as old as Ajay 10 years back. How old is Ajay today if Sachin will be 40 years old 10 years hence
- 18
- 25
- 15
- 20
Answer: Option D
Explanation:
Sachin's age today = 30 years.
Sachin's age 10 years back = 20 years.
Ajay's age 10 years back = 10 years.
Ajay's age today =20 years
5. A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is
- 20 years
- 21 years
- 22 years
- 24 years
Answer: Option C
Explanation:
Let the son's present age be x years. Then, man's present age = (x + 24) years
=> (x + 24) + 2 = 2(x + 2)
=> x + 26 = 2x + 4
So, x = 22
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