Question Detail
3640 ÷ 14*16 + 340 = ?
- 3500
- 4500
- 1500
- 2500
Answer: Option B
1. The number of girls in a class are 7 times the number of boys, which value can never be the of total students
- 40
- 48
- 24
- 30
Answer: Option D
Explanation:
Let the boys are X, then girls are 7X, total = X+7X = 8X
So it should be multiple of 8, 30 is not a multiple of 8.
2. \begin{aligned}
\frac{4+4 \times 18 -6 - 8}{123 \times 6 - 146 \times 5 }
\end{aligned}
- 7.50
- 7.75
- 8
- 8.05
Answer: Option B
Explanation:
\begin{aligned}
\frac{4+72-6-8}{738-730}
\end{aligned}
\begin{aligned}
= \frac{76-14}{8}
\end{aligned}
\begin{aligned}
= \frac{62}{8} = 7.75
\end{aligned}
3. In a class free notebooks were distributed among all the children. Each child got notebooks which were one-eighth of the number of children. If number of children been half, then each child would have recieved 16 notebooks in total. Find the total number of books distributed.
- 450
- 512
- 598
- 658
Answer: Option B
Explanation:
Let suppose total number of students in class are X.
Then from the question we can conclude it that,
\begin{aligned}
X*\frac{1}{8}X = \frac{X}{2}*16 \\
=> X = 64\\
\text{Total notebooks,} \\
= \frac{1}{8}X^2 \\
= \left( \frac{1}{8} * 64 * 64 \right) \\
= 512
\end{aligned}
4. 100 + 50 * 2 = ?
- 200
- 150
- 100
- 300
Answer: Option A
Explanation:
After applying BOMAS rule,
First Multiplication will be done then addition
So it will be 100 + 100 = 200
5. Simplify
\begin{aligned}
\frac{\frac{7}{2}\div {\frac{5}{2}} \times {\frac{3}{2}} }{\frac{7}{2} \div { \frac{5}{2}} of \frac{3}{2} } \div 5.25
\end{aligned}
- \begin{aligned} \frac{3}{5} \end{aligned}
- \begin{aligned} \frac{3}{6} \end{aligned}
- \begin{aligned} \frac{3}{7} \end{aligned}
- \begin{aligned} \frac{3}{8} \end{aligned}
Answer: Option C
Explanation:
\begin{aligned}
\frac{\frac{7}{2}\div {\frac{5}{2}} \times {\frac{3}{2}} }{\frac{7}{2} \div { \frac{5}{2}} of \frac{3}{2} }\div 5.25
\end{aligned}
\begin{aligned}
= \frac{\frac{7}{2}\times {\frac{2}{5}} \times {\frac{3}{2}} }{\frac{7}{2} \div { \frac{15}{4}}}\div 5.25
\end{aligned}
\begin{aligned}
= \frac{\frac{21}{10}}
{\frac{7}{2} \times { \frac{4}{15}}}\div {\frac{525}{100}}
\end{aligned}
\begin{aligned}
= \frac{21}{10}\times{\frac{15}{14}}\times\frac{100}{525}
= \frac{6}{14}
= \frac{3}{7}
\end{aligned}