Evaluate
\begin{aligned}
\sqrt{1\frac{9}{16}}
\end{aligned}

Answer: Option B

Explanation:

\begin{aligned}
= \frac{2707}{27.07} = \sqrt{x}
\end{aligned}

\begin{aligned}
=> \frac{2707 \times 100}{2707} = \sqrt{x}
\end{aligned}

\begin{aligned}
=> 100 = \sqrt{x}
\end{aligned}

\begin{aligned}
=> x = 100^2 = 10000
\end{aligned}

Answer: Option B

Explanation:

\begin{aligned}
=> \sqrt{81} + \sqrt{0.81} = 10.09 - X
\end{aligned}

\begin{aligned}
=> 9 + 0.9 = 10.09 - X
\end{aligned}

\begin{aligned}
=> X = 10.09 - 9.9 = 0.19
\end{aligned}

Answer: Option C

Explanation:

\begin{aligned}
= (\frac{25}{11} \times \frac{14}{5} \times \frac{11}{14})
\end{aligned}

\begin{aligned}
= 5
\end{aligned}

Answer: Option D

Explanation:

Tip: Please check the question carefully before answering. As 3a is not under the root we can convert it into a formula , lets evaluate now :

\begin{aligned}
= \sqrt{4a^2 - 4a + 1} + 3a \end{aligned}

\begin{aligned}
= \sqrt{(1)^2 + (2a)^2 - 2x1x2a} + 3a \end{aligned}

\begin{aligned}
= \sqrt{(1-2a)^2} + 3a \end{aligned}

\begin{aligned}
= (1-2a) + 3a \end{aligned}

\begin{aligned}
= (1-2a) + 3a \end{aligned}

\begin{aligned}
= 1 + a = 1 + 0.1039 = 1.1039 \end{aligned}

Answer: Option A

Explanation:

\begin{aligned}
3600 = 2^3 \times 5^2 \times 3^2 \times 2
\end{aligned}
To make it a perfect cube it must be divided by
\begin{aligned}
5^2 \times 3^2 \times 2 = 450
\end{aligned}