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Find the HCF of
\begin{aligned}
2^2 \times 3^2 \times 7^2, 2 \times 3^4 \times 7
\end{aligned}

  • 128
  • 126
  • 146
  • 434

Answer: Option B

Explanation:

HCF is Highest common factor, so we need to get the common highest factors among given values. So we got
2 * 3*3 * 7

Similar Questions :

1. What will be the LCM of 8, 24, 36 and 54

  • 54
  • 108
  • 216
  • 432

Answer: Option C

Explanation:

LCM of 8-24-36-54 will be
2*2*2*3*3*3 = 216

2. Find the HCF of \begin{aligned} \frac{2}{3}, \frac{4}{6}, \frac{8}{27} \end{aligned}

  • \begin{aligned} \frac{2}{27} \end{aligned}
  • \begin{aligned} \frac{8}{3} \end{aligned}
  • \begin{aligned} \frac{2}{3} \end{aligned}
  • \begin{aligned} \frac{8}{27} \end{aligned}

Answer: Option A

Explanation:

Whenever we have to solve this sort of question, remember the formula.
HCF = \begin{aligned} \frac{HCF of Numerators}{LCM of Denominators} \end{aligned}
So answers will be option 1

3. Find the greatest number that will divide 400, 435 and 541 leaving 9, 10 and 14 as remainders respectively

  • 19
  • 17
  • 13
  • 9

Answer: Option B

Explanation:

Answer will be HCF of (400-9, 435-10, 541-14)

HCF of (391, 425, 527) = 17

4. Find the largest number of four digits which is exactly divisible by 27,18,12,15

  • 9700
  • 9710
  • 9720
  • 9730

Answer: Option C

Explanation:

LCM of 27-18-12-15 is 540.
After dividing 9999 by 540 we get 279 remainder.
So answer will be 9999-279 = 9720

5. If LCM of two number is 693, HCF of two numbers is 11 and one number is 99, then find other

  • 34
  • 77
  • 12
  • 45

Answer: Option B

Explanation:

For any this type of question, remember
Product of two numbers = Product of their HCF and LCM

So Other number = \begin{aligned} \frac{693 \times 11}{99} \end{aligned} = 77

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