Question Detail

Find the value of x
\begin{aligned}
\frac{2707}{\sqrt{x}} = 27.07
\end{aligned}

1000
10000
10000000
None of above

Answer: Option B

Explanation:

\begin{aligned}
= \frac{2707}{27.07} = \sqrt{x}
\end{aligned}

\begin{aligned}
=> \frac{2707 \times 100}{2707} = \sqrt{x}
\end{aligned}

\begin{aligned}
=> 100 = \sqrt{x}
\end{aligned}

\begin{aligned}
=> x = 100^2 = 10000
\end{aligned}

1. The cube root of .000216 is

0.6
0.006
0.06
.0006

Answer: Option C

2. Students of a class collected as many paise from each student of class as is the number of students in that class. If total collection is Rs. 59.29, then find the total number of students in the class.

Answer: Option C

Explanation:

So from the question it is clear that total sum collected was 59.29 rupees.
So total paise are 5929.
\begin{aligned}
\text{Total Members = } \sqrt{5929} \\
= 77
\end{aligned}

3. \begin{aligned}
(\frac{\sqrt{625}}{11} \times \frac{14}{\sqrt{25}} \times \frac{11}{\sqrt{196}})
\end{aligned}

Answer: Option C

Explanation:

\begin{aligned}
= (\frac{25}{11} \times \frac{14}{5} \times \frac{11}{14})
\end{aligned}

\begin{aligned}
= 5
\end{aligned}

4. if a = 0.1039, then the value of
\begin{aligned} \sqrt{4a^2 - 4a + 1} + 3a \end{aligned}

12.039
1.2039
11.039
1.1039

Answer: Option D

Explanation:

Tip: Please check the question carefully before answering. As 3a is not under the root we can convert it into a formula , lets evaluate now :

\begin{aligned}
= \sqrt{4a^2 - 4a + 1} + 3a \end{aligned}

\begin{aligned}
= \sqrt{(1)^2 + (2a)^2 - 2x1x2a} + 3a \end{aligned}

\begin{aligned}
= \sqrt{(1-2a)^2} + 3a \end{aligned}

\begin{aligned}
= (1-2a) + 3a \end{aligned}

\begin{aligned}
= (1-2a) + 3a \end{aligned}

\begin{aligned}
= 1 + a = 1 + 0.1039 = 1.1039 \end{aligned}

5. Evaluate
\begin{aligned}
\sqrt{1\frac{9}{16}}
\end{aligned}

\begin{aligned} 1\frac{1}{6} \end{aligned}
\begin{aligned} 1\frac{1}{5} \end{aligned}
\begin{aligned} 1\frac{1}{4} \end{aligned}
\begin{aligned} 1\frac{1}{3} \end{aligned}

Answer: Option C

Explanation:

\begin{aligned}
= \sqrt{\frac{25}{16}}
\end{aligned}

\begin{aligned}
= \frac{\sqrt{25}}{\sqrt{16}}
\end{aligned}

\begin{aligned}
= \frac{5}{4}
\end{aligned}

\begin{aligned}
= 1\frac{1}{4}
\end{aligned}

Question Detail

Find the value of x \begin{aligned} \frac{2707}{\sqrt{x}} = 27.07 \end{aligned}

1. The cube root of .000216 is

2. Students of a class collected as many paise from each student of class as is the number of students in that class. If total collection is Rs. 59.29, then find the total number of students in the class.

3. \begin{aligned} (\frac{\sqrt{625}}{11} \times \frac{14}{\sqrt{25}} \times \frac{11}{\sqrt{196}}) \end{aligned}

4. if a = 0.1039, then the value of \begin{aligned} \sqrt{4a^2 - 4a + 1} + 3a \end{aligned}

5. Evaluate \begin{aligned} \sqrt{1\frac{9}{16}} \end{aligned}

Find the value of x
\begin{aligned}
\frac{2707}{\sqrt{x}} = 27.07
\end{aligned}

3. \begin{aligned}
(\frac{\sqrt{625}}{11} \times \frac{14}{\sqrt{25}} \times \frac{11}{\sqrt{196}})
\end{aligned}

4. if a = 0.1039, then the value of
\begin{aligned} \sqrt{4a^2 - 4a + 1} + 3a \end{aligned}

5. Evaluate
\begin{aligned}
\sqrt{1\frac{9}{16}}
\end{aligned}