Question Detail

How many pieces of 0.85 meteres can be cut from a rod 42.5 meteres long

Answer: Option C

Explanation:

We need so simple divide 42.5/0.85,
=(4250/85) = 50

1. The number of girls in a class are 7 times the number of boys, which value can never be the of total students

Answer: Option D

Explanation:

Let the boys are X, then girls are 7X, total = X+7X = 8X

So it should be multiple of 8, 30 is not a multiple of 8.

2. \begin{aligned}
\frac{4+4 \times 18 -6 - 8}{123 \times 6 - 146 \times 5 }
\end{aligned}

7.50
7.75
8
8.05

Answer: Option B

Explanation:

\begin{aligned}
\frac{4+72-6-8}{738-730}
\end{aligned}
\begin{aligned}
= \frac{76-14}{8}
\end{aligned}
\begin{aligned}
= \frac{62}{8} = 7.75
\end{aligned}

3. Along a yard 225 metres long, 26 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between two consecutive trees

Answer: Option B

Explanation:

26 trees have 25 gaps between them,
Required distance (225/25) = 10

4. Value of
\begin{aligned}
\frac{1}{2+\frac{1}{2+\frac{1}{2-\frac{1}{2}}}}

\end{aligned}

\begin{aligned} \frac{6}{19} \end{aligned}
\begin{aligned} \frac{7}{19} \end{aligned}
\begin{aligned} \frac{8}{19} \end{aligned}
\begin{aligned} \frac{9}{19} \end{aligned}

Answer: Option C

Explanation:

\begin{aligned}
= \frac{1}{2+\frac{1}{2+\frac{1}{\frac{3}{2}}}}
\end{aligned}
\begin{aligned}
= \frac{1}{2+\frac{1}{2+\frac{2}{3}}}
\end{aligned}

\begin{aligned}
= \frac{1}{2+\frac{1}{\frac{8}{3}}}
\end{aligned}

\begin{aligned}
= \frac{1}{2+\frac{3}{8}}
\end{aligned}

\begin{aligned}
= \frac{1}{\frac{19}{8}}
\end{aligned}

\begin{aligned}
= \frac{8}{19}
\end{aligned}

5. (3080 + 6160) / 28

Answer: Option C

Explanation:

As per BODMAS rule, first we will solve the equation in bracket then we will go for division
= (9240)/28 = 330

Question Detail

How many pieces of 0.85 meteres can be cut from a rod 42.5 meteres long

1. The number of girls in a class are 7 times the number of boys, which value can never be the of total students

2. \begin{aligned} \frac{4+4 \times 18 -6 - 8}{123 \times 6 - 146 \times 5 } \end{aligned}

3. Along a yard 225 metres long, 26 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between two consecutive trees

4. Value of \begin{aligned} \frac{1}{2+\frac{1}{2+\frac{1}{2-\frac{1}{2}}}} \end{aligned}

5. (3080 + 6160) / 28

2. \begin{aligned}
\frac{4+4 \times 18 -6 - 8}{123 \times 6 - 146 \times 5 }
\end{aligned}

4. Value of
\begin{aligned}
\frac{1}{2+\frac{1}{2+\frac{1}{2-\frac{1}{2}}}}

\end{aligned}