Question Detail
If 100 cats kill 100 mice in 100 days, then 4 cats would kill 4 mice in how many days ?
- 4 day
- 10 day
- 40 day
- 100 day
Answer: Option D
1. In a chess tournament each of six players will play every other player exactly once. How many matches will be played during the tournament ?
- 12
- 15
- 30
- 36
Answer: Option B
Explanation:
I. matches of first player with other 5 players
II. matches of second player with 4 players other than the first player
III. matches of third player with 3 players other than the first player and second player.
IV. matches of fourth player with 2 players other than the first player, second player and third player.
V. matches of fifth player with 1 player other than the first player, second player, third player and fourth player.
So total matches will be 5+4+3+2+1 = 15
2. A shepherd had 27 sheep. All but 10 died. How many he left with ?
- 10
- 15
- 17
- 27
Answer: Option A
Explanation:
"All but 10 died" means all except 10 died, so he is remained with 10 sheep.
3. Aruna cut a cake into two halves and cuts one half into smaller pieces of equal size. Each of the small pieces is twenty grams in weight. If she has seven pieces of the cake in all with her, how heavy was the original cake ?
- 240 gm
- 220 gm
- 225 gm
- 250 gm
Answer: Option A
Explanation:
Seven pieces consist of 6 smaller equal pieces and one half cake piece.
Weight of each small piece = 20 gm
So, total weight of the cake = 2 (20 * 6) = 240 gm
4. A, B, C and D play a game of cards. A says to B. "If I give you 8 cards, you will have as many as C has and I shall have 3 less than what C has. Also if I take 8 cards from C, I shall have twice as many as D has." If B and D together have 50 cards, how many cards have A got?
- 35
- 37
- 38
- 40
Answer: Option D
Explanation:
If we read given question carefully, we get,
B+8 = C ---(i)
A-8 = C-3 ---(ii)
A+6 = 2D ---(iii)
B+D = 50 ---(iv)
Putting C = A -5 from (ii) into (i), we have :
B+8 = A-5 or A-B = 13 ---(v)
Putting D = 50-B from (iv) and (iii), we have :
A+6 = 100-2B or A+2B = 94 ---(vi)
Solving (v) and (vi), we get
B = 27 and A = 40
5. A is three times as old as B. C was twice-as old as A four years ago. In four years' time, A will be 31. What are the present ages of B and C ?
- 9, 46
- 9, 50
- 10, 46
- 10, 50
Answer: Option B
Explanation:
As from the question we have,
A = 3B --- (i)
c - 4 = 2(A+4) ---(ii)
Also, A + 4 = 31
or A = 31-4 = 27
Putting A = 27 in (i) we get
B = 9
Putting A = 27 in (ii) we get
C = 50