Question Detail

If COMPLETED is coded as MOCELPDET, then DIRECTION will be coded as :

RIDTCENOJ
SIDTCENOI
RIDTCENOI
RIETCENOI

Answer: Option C

Explanation:

In given word, word is divided into three parts like
COM+PLE+TED, then these parts are written in reverse order as

MOC+ELP+DET

So DIRECTION will be DIR+ECT+ION,
which will be RIDTCENOI

1. If JOSEPH is coded as FKOALD, then GEORGE will be coded as :

CAKNCA
HAKNCA
CBKNCA
CALNCA

Answer: Option A

Explanation:

Each letter of the word is moved four step back to decode it.
So GEORGE will be CAKNCA

2. In a certain code, SIKKIM is written as THLJJL, how is TRAINING written in that code ?

SQBHOHOF
UQBHOIOF
UQBHOHOI
UQBHOHOF

Answer: Option D

Explanation:

In given word, word is increasing and decreasing by one alternatively as,
S +1 T
I -1 H
K +1 L
K -1 J
I +1 J
M -1 L

So in the same way TRAINING will be UQBHOHOF

3. If COOL is coded as DQRP, then write the code for HOT

Answer: Option B

Explanation:

In COOL, first letter is increased by 1, second by 2, third by 3 and so on.

So HOT will be coded as,
H+1 I
O+2 Q
T+3 W

So it will be IQW

4. In a certain language, MADRAS is coded as NBESBT, how is BOMBAY coded in that code ?

CPNCBZ
CPNCBX
DPNCBZ
DPNCBX

Answer: Option A

Explanation:

Clearly every letter is increased by 1 as
M +1 N
A +1 B
D +1 E
R +1 S
A +1 B
S +1 T

So after increasing every character in work BOMBAY by 1, we get

5. If FRIEND is coded as HUMJTK, how is CANDLE written in that code ?

EDRIRL
DCQHQK
DEQJQM
FYOBOC

Answer: Option A

Explanation:

The first, second, third, fourth, fifth and sixth letters of th word are respectively moved two, three, four, five, six and seven steps forward to obtain the corresponding letters of the code.

So CANDLE will be coded as EDRIRL.