Question Detail
In a group of 15 people, 7 read French, 8 read English while 3 of them read none of these two. How many of them read French and English both ?
- 2
- 3
- 4
- 5
Answer: Option B
1. In a chess tournament each of six players will play every other player exactly once. How many matches will be played during the tournament ?
- 12
- 15
- 30
- 36
Answer: Option B
Explanation:
I. matches of first player with other 5 players
II. matches of second player with 4 players other than the first player
III. matches of third player with 3 players other than the first player and second player.
IV. matches of fourth player with 2 players other than the first player, second player and third player.
V. matches of fifth player with 1 player other than the first player, second player, third player and fourth player.
So total matches will be 5+4+3+2+1 = 15
2. In a caravan, in addition to 50 hens, there are 45 goats and 8 camels with some keepers. If the total number of feet be 224 more than the number of heads in the caravan, the number of keepers is
- 5
- 8
- 10
- 15
Answer: Option D
Explanation:
Let the number of keepers be x.
Then, total number of feet = 2*50+4*45+4*8+2x
= 2x + 312
Total number of heads = 50+45+8+x = 103 + x
Now, (2x+312) = (103+x)+224
=> x = 15
3. A father is now three times as old as his son. Five years back, he was four times as old as his son. The age of the son is :
- 12
- 15
- 18
- 20
Answer: Option B
Explanation:
Let son's age be x then father's age is 3x
Five years ago, father's age = 3x-5 and son's age x-5
So, 3x-5 = 4(x-5)
=> 3x-5 = 4x-20
=> x = 15
4. I have a few sweets to be distributed. If I keep 2, 3 or 4 in a pack, I am left with one sweet. If I keep 5 in a pack, I am left with none. What is the minimum number of sweets I have to pack and distribute ?
- 25
- 37
- 54
- 65
Answer: Option A
Explanation:
The required number will be such that it leaves a reminder of 1 when divided by 2, 3 or 4 and no reminder when divided by 5. Such a number is 25 among options
5. A, B, C and D play a game of cards. A says to B. "If I give you 8 cards, you will have as many as C has and I shall have 3 less than what C has. Also if I take 8 cards from C, I shall have twice as many as D has." If B and D together have 50 cards, how many cards have A got?
- 35
- 37
- 38
- 40
Answer: Option D
Explanation:
If we read given question carefully, we get,
B+8 = C ---(i)
A-8 = C-3 ---(ii)
A+6 = 2D ---(iii)
B+D = 50 ---(iv)
Putting C = A -5 from (ii) into (i), we have :
B+8 = A-5 or A-B = 13 ---(v)
Putting D = 50-B from (iv) and (iii), we have :
A+6 = 100-2B or A+2B = 94 ---(vi)
Solving (v) and (vi), we get
B = 27 and A = 40