Question Detail
Simplify
(31/10) * (3/10) + (7/5) / 20
- 0
- 1
- 10
- 100
Answer: Option B
Explanation:
= (31/10) * (3/10) + (7/5) / 20
= (3.1) * (.3) + (1.4) / 20
= 0.93 + 0.07
= 1
1. Simplify
\begin{aligned} 1+\frac{1}{2}+\frac{1}{4}+\frac{1}{7}+\frac{1}{14}+\frac{1}{28} = ? \end{aligned}
- 2
- 2.3
- 2.6
- 5
Answer: Option A
Explanation:
By taking LCM we get
=\begin{aligned} \frac{28+14+7+4+2+1}{28}
= \frac{56}{28} = 2\end{aligned}
2. Company workers decided to raise Rs. 3 lakhs by equal contribution from each. Had they contributed Rs. 50 each extra, the contribution would have been Rs. 3.25 lakhs. How many workers were they?
- 300
- 400
- 500
- 600
Answer: Option C
Explanation:
N * 50 = (325000 - 300000) = 25000
N = 25000 / 50
= 500
3. Simplify
\begin{aligned}
\frac{\frac{7}{2}\div {\frac{5}{2}} \times {\frac{3}{2}} }{\frac{7}{2} \div { \frac{5}{2}} of \frac{3}{2} } \div 5.25
\end{aligned}
- \begin{aligned} \frac{3}{5} \end{aligned}
- \begin{aligned} \frac{3}{6} \end{aligned}
- \begin{aligned} \frac{3}{7} \end{aligned}
- \begin{aligned} \frac{3}{8} \end{aligned}
Answer: Option C
Explanation:
\begin{aligned}
\frac{\frac{7}{2}\div {\frac{5}{2}} \times {\frac{3}{2}} }{\frac{7}{2} \div { \frac{5}{2}} of \frac{3}{2} }\div 5.25
\end{aligned}
\begin{aligned}
= \frac{\frac{7}{2}\times {\frac{2}{5}} \times {\frac{3}{2}} }{\frac{7}{2} \div { \frac{15}{4}}}\div 5.25
\end{aligned}
\begin{aligned}
= \frac{\frac{21}{10}}
{\frac{7}{2} \times { \frac{4}{15}}}\div {\frac{525}{100}}
\end{aligned}
\begin{aligned}
= \frac{21}{10}\times{\frac{15}{14}}\times\frac{100}{525}
= \frac{6}{14}
= \frac{3}{7}
\end{aligned}
4. 3640 ÷ 14*16 + 340 = ?
- 3500
- 4500
- 1500
- 2500
Answer: Option B
5. In a class free notebooks were distributed among all the children. Each child got notebooks which were one-eighth of the number of children. If number of children been half, then each child would have recieved 16 notebooks in total. Find the total number of books distributed.
- 450
- 512
- 598
- 658
Answer: Option B
Explanation:
Let suppose total number of students in class are X.
Then from the question we can conclude it that,
\begin{aligned}
X*\frac{1}{8}X = \frac{X}{2}*16 \\
=> X = 64\\
\text{Total notebooks,} \\
= \frac{1}{8}X^2 \\
= \left( \frac{1}{8} * 64 * 64 \right) \\
= 512
\end{aligned}