Navigate

Question Detail

The average score of a cricketer for ten matches is 38.9 runs. If the average for first six matches is 42, then average for last four matches is

  • 33.25
  • 32.25
  • 34.25
  • 34.50

Answer: Option C

Explanation:

\begin{aligned}
= \frac{(38.9 \times 10)-(42 \times 6)}{4}
\end{aligned}

\begin{aligned}
= \frac{(1216 - 750)}{4} = 34.25
\end{aligned}

Similar Questions :

1. Average of 10 matches is 32, How many runs one should should score to increase his average by 4 runs.

  • 70
  • 76
  • 78
  • 80

Answer: Option B

Explanation:

Average after 11 innings should be 36

So, Required score = (11 * 36) - (10 * 32)
= 396 - 320 = 76

2. A batsman makes a score of 87 runs in the 17th match and thus increases his average by 3. Find his average after 17th match

  • 36
  • 37
  • 38
  • 39

Answer: Option D

Explanation:

Let the average after 17th match is x
then the average before 17th match is x-3

so 16(x-3) + 87 = 17x
=> x = 87 - 48 = 39

3. The average of six numbers is X and the average of three of these is Y.If the average of the remaining three is z, then

  • x = y + z
  • 2x = y + z
  • x = 2y + z
  • x = y + 2z

Answer: Option B

Explanation:

X =((3y+3z)/6)
or
2X= y + z

4. Reeya obtained 65, 67, 76, 82 and 85 out of 100 in different subjects, What will be the average.

  • 70
  • 75
  • 80
  • 85

Answer: Option B

Explanation:

\begin{aligned}
( \frac {65+67+76+82+85}{5} ) = 75
\end{aligned}

5. Average of first five multiples of 3 is

  • 9
  • 11
  • 13
  • 15

Answer: Option A

Explanation:

\begin{aligned}
Average = \frac{3(1+2+3+4+5)}{5} = \frac{45}{5} = 9
\end{aligned}

Read more from - Average Questions Answers