Question Detail The largest four digit number which is a perfect cube, is: 7000800092619999 Answer: Option CExplanation:21*21*21 = 9261 Similar Questions : 1. The least perfect square, which is divisible by each of 21, 36 and 66 is 213414213424213434213444 Answer: Option DExplanation:L.C.M. of 21, 36, 66 = 2772 Now, 2772 = 2 x 2 x 3 x 3 x 7 x 11 To make it a perfect square, it must be multiplied by 7 x 11. So, required number = 2 x 2 x 3 x 3 x 7 x 7 x 11 x 11 = 213444 2. Evaluate \begin{aligned} \sqrt{0.00059049} \end{aligned} 0.002430.02430.2432.43 Answer: Option BExplanation:Very obvious tip here is, after squre root the terms after decimal will be half (that is just a trick), works awesome at many questions like this. 3. Evaluate \begin{aligned} \sqrt{1\frac{9}{16}} \end{aligned} \begin{aligned} 1\frac{1}{6} \end{aligned}\begin{aligned} 1\frac{1}{5} \end{aligned}\begin{aligned} 1\frac{1}{4} \end{aligned}\begin{aligned} 1\frac{1}{3} \end{aligned} Answer: Option CExplanation:\begin{aligned} = \sqrt{\frac{25}{16}} \end{aligned} \begin{aligned} = \frac{\sqrt{25}}{\sqrt{16}} \end{aligned} \begin{aligned} = \frac{5}{4} \end{aligned} \begin{aligned} = 1\frac{1}{4} \end{aligned} 4. The cube root of .000216 is 0.60.0060.06.0006 Answer: Option C 5. Evaluate \begin{aligned} \sqrt[3]{4\frac{12}{125}} \end{aligned} \begin{aligned} 1\frac{2}{5} \end{aligned}\begin{aligned} 1\frac{3}{5} \end{aligned}\begin{aligned} 1\frac{4}{5} \end{aligned}1 Answer: Option BExplanation:\begin{aligned} = \sqrt[3]{\frac{512}{125}} \end{aligned} \begin{aligned} = (\frac{8*8*8}{5*5*5})^{\frac{1}{3}} \end{aligned} \begin{aligned} = \frac{8}{5} = 1\frac{3}{5} \end{aligned} Read more from - Square Root and Cube Root Questions Answers