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The sum of the present ages of a father and his son is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be

  • 15 years
  • 18 years
  • 20 years
  • 22 years

Answer: Option C

Explanation:

Clue : (60 - x) - 6 = 5(x - 6)

Similar Questions :

1. Raju age after 15 years will be 5 times his age 5 years back, What is the present age of Raju

  • 15
  • 14
  • 10
  • 8

Answer: Option C

Explanation:

Clearly,
x+15 = 5(x-5)
<=> 4x = 40 => x = 10

2. Total of the ages of A, B ahd C at present is 90 years. Ten years ago, the ratio of their ages was 1: 2: 3. What is the age of B at present

  • 25
  • 30
  • 45
  • 60

Answer: Option B

Explanation:

Let their ages 10 years ago is x, 2x and 3x years.
10 + 2x + 10 + 3x + 10 = 90 hence x= 10
B’s present age = (2x + 10) =30 years

3. The ages of two persons differ by 20 years. If 5 years ago, the elder one be 5 times as old as the younger one, their present ages (in years) are respectively

  • 20,20
  • 20,10
  • 25,15
  • 30,10

Answer: Option D

Explanation:

Let their ages be x and (x + 20) years.
5 (x - 5) = (x + 20 - 5) or 4x = 40 or x = 10.
Their present ages are 30 years and 10 years

4. The sum of the ages of a father and son is 45 years. Five years ago, the product of their ages was four times the fathers age at that time. The present age of father and son

  • 34,11
  • 35,10
  • 36,9
  • 40,5

Answer: Option C

Explanation:

Let sons age = x years. Then fathers age = (45 - x)years.
(x—5)(45—x—5) = 4(45- x - 5) hence (x—5) = 4 so x = 9
Their ages are 36 years and 9 years.

5. In 10 years, A will be twice as old5as B was 10 years ago. If A is now 9 years older than B, the present age of B is

  • 35
  • 37
  • 39
  • 41

Answer: Option C

Explanation:

Let B's age = x years.
Then, As age = (x+ 9) years.
(x+9+10)=2(x—10)
hence x=39.
Present age of B = 39 years

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