Question Detail

7589 - X = 3434

4155
2321
3155
None of above

Answer: Option A

1. What is the largest 4 digit number exactly divisible by 88

9900
9999
9988
9944

Answer: Option D

Explanation:

Largest 4 digit number is 9999
After doing 9999 ÷ 88 we get remainder 55
Hence largest 4 digit number exactly divisible by 88 = 9999 - 55 = 9944

2. \begin{aligned}
46^2 - (?)^2 = 4398 - 3066
\end{aligned}

Answer: Option D

3. What least value should be replaced by * in 223*431 so the number become divisible by 9

Answer: Option A

Explanation:

Trick: Number is divisible by 9, if sum of all digits is divisible by 9, so (2+2+3+*+4+3+1) = 15+* should be divisible by 9,
15+3 will be divisible by 9,
so that least number is 3.

4. The greatest number by which the product of three consecutive multiples of 3 is always

Answer: Option C

Explanation:

3*6*9 = 162

5. 1307 * 1307 = ?

1608249
1508249
1408249
1708249

Answer: Option D

Explanation:

\begin{aligned}
(a + b)^{2} = (a^2 + b^2 + 2ab)
\end{aligned}
\begin{aligned}
1307^{2} = (1300 + 7)^2 = (1690000 + 49 + 18200)
\end{aligned}

Question Detail

7589 - X = 3434

1. What is the largest 4 digit number exactly divisible by 88

2. \begin{aligned} 46^2 - (?)^2 = 4398 - 3066 \end{aligned}

3. What least value should be replaced by * in 223*431 so the number become divisible by 9

4. The greatest number by which the product of three consecutive multiples of 3 is always

5. 1307 * 1307 = ?

2. \begin{aligned}
46^2 - (?)^2 = 4398 - 3066
\end{aligned}