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Numbers Questions Answers

  • 1. Simplify 586645 * 9999

    1. 5865863355
    2. 5665863355
    3. 4865863355
    4. 4665863355
    Answer And Explanation

    Answer: Option A

    Explanation:

    Although it is a simple question, but the trick is to save time in solving this.
    Rather than multiplying it we can do as follows:
    586645 * (10000 - 1) = 5866450000 - 586645 = 5865863355

  • 2. 1939392 * 625

    1. 1212120010
    2. 1212120000
    3. 1212120011
    4. 1212121010
    Answer And Explanation

    Answer: Option B

    Explanation:

    Trick: when multiplying with \begin{aligned} 5^n
    \end{aligned} then put n zeros to the right of multiplicand and divide the number with \begin{aligned} 2^n
    \end{aligned}
    So using this we can solve this question in much less
    time.
    \begin{aligned} 1939392 \times 5^4 = \frac {19393920000}{16} = 1212120000
    \end{aligned}

  • 3. Simplify (212 * 212 + 312 * 312 )

    1. 132288
    2. 142088
    3. 142188
    4. 142288
    Answer And Explanation

    Answer: Option D

    Explanation:

    Trick: Above equation can be solved by using following formula
    \begin{aligned}
    (a^2 + b^2) = \frac{1}{2}((a+b)^2 + (a-b)^2)
    \end{aligned}

  • 4. Find the unit digit in \begin{aligned}
    (544)^{102} + (544)^{103}
    \end{aligned}

    1. 2
    2. 4
    3. 0
    4. 1
    Answer And Explanation

    Answer: Option C

    Explanation:

    Required digit is = \begin{aligned}
    (4)^{102} + (4)^{103} \end{aligned}
    as \begin{aligned} (4)^2 \end{aligned} gives unit digit 6 so \begin{aligned} (4)^{102} \end{aligned} unit digit is 6 and \begin{aligned} (4)^{103} \end{aligned} unit digit is, unit digit of \begin{aligned} 6 \times 4 \end{aligned}= 4, so answer will be unit digit of 6 + 4 = 0

  • 5. What least value should be replaced by * in 223*431 so the number become divisible by 9

    1. 3
    2. 4
    3. 5
    4. 6
    Answer And Explanation

    Answer: Option A

    Explanation:

    Trick: Number is divisible by 9, if sum of all digits is divisible by 9, so (2+2+3+*+4+3+1) = 15+* should be divisible by 9,
    15+3 will be divisible by 9,
    so that least number is 3.

  • 6. How many terms are there in 2,4,8,16,....,1024

    1. 7
    2. 8
    3. 9
    4. 10
    Answer And Explanation

    Answer: Option D

    Explanation:

    It is a GP. with r = 2, ie \begin{aligned} 2^1, 2^2, 2^3... \end{aligned}
    If number of terms is n. Then,
    \begin{aligned} 2 \times 2^{n-1} = 1024 \end{aligned} =>
    \begin{aligned} 2^{n-1} = 512 \end{aligned}
    or \begin{aligned} 2 \times 2^{n-1} = 2^9 \end{aligned}
    so n-1 = 9 => n = 10

  • 7. Which of the following is a prime number

    1. 9
    2. 2
    3. 4
    4. 8
    Answer And Explanation

    Answer: Option B

    Explanation:

    A prime number is a natural number greater than 1 which has no positive divisors other than 1 or itself.
    So from above options 2 is that number

Post a comment

  • Badra Kiringoda 1 year ago

    this site gives more. no site will be give this informations in free. Great works.

  • pialee sarkar 2 years ago

    thank u....

  • Sachin Yadav 2 years ago

    FlizzINdia free online test series for Upcoming Competitive exams

  • Srikanth Boddula 3 years ago

    Good site bro...put more different types of problems

  • Br@inWa$h 3 years ago

    plz provide more difficult questions.
    u can provide some previous year questions also

  • idhal 3 years ago

    we expect more difficult questions from you...

  • Aravind Kumaran Ramesh 3 years ago

    NICE SITE FOR APTITUDE PREPARATION....THANK U

  • akash singh 3 years ago

    Good collection of math question for starter/fresher,
    but plz include more question which matches difficulty level of the question that come in exam

    mastguru 3 years ago replied

    Sure Akash, thanks for feedback !

  • Akash 3 years ago

    Good collection of math question for starter/fresher,
    but plz include more question which matches difficulty level of the question that come in exam.

  • shekhar 3 years ago

    first i want to thank you for ur effort but please add few more question.

    mastguru 3 years ago replied

    Thank you Shekhar for your feedback.. we are working on it !

  • Naveen Kumar C 3 years ago

    Some more questions sir

    mastguru 3 years ago replied

    Sure Friend !

  • Tanay Kumar Das 3 years ago

    TOP IBPS CWE PO EXAM 2015 STUDY MATERIAL COACHING SYLLABUS TIPS TRICKS BOOKS PREPARATION PLANS AT http://tsa1998.blogspot.in/201...

  • Ashish Kumar 3 years ago

    I really appreciated with this web for kind of support for competitive exams.

    But if u try to find some technical questions & answers like sail, vizag steel, CIL, NMDC, etc., it would be good.

    mastguru 3 years ago replied

    Sure Ashish, thanks for your feedback !

  • Abhijit Debnath 3 years ago

    Style of the site is very good it gives extra willing to stay on the site and make solve questions than other sites.Computer awareness questions were superb but Quantitives should be highly modified.

    mastguru 3 years ago replied

    Sure Abhijit. thanks for your feedback !

  • Sitam Mohanty 4 years ago

    Best site to prepare for competitive exam.More math tricks should be added and current affairs should be organised in more user friendly way.Thank U

    mastguru 4 years ago replied

    Thank you Sitam.. for your feedback..

  • Rajesh Bagodi 4 years ago

    It really helps!!

  • ????? ??? 4 years ago

    thanks sir.. plz upload more tricks.. :)

    mastguru 4 years ago replied

    Welcome friend..

  • Vijay Kiran R 4 years ago

    Error in question 6

    2×2^n?1=2^9 is wrong...

    It must be
    2×2^n?1=2^10

  • Adarsha 4 years ago

    finally thanks for this valuable information

    mastguru 4 years ago replied

    Thank you Adarsha for your feedback.

  • Vignesh 4 years ago

    Increase the number of questions

    mastguru 4 years ago replied

    Sure Vignesh ji.. We are working with it..

  • sunny 5 years ago

    LOD is not that gud :(

  • eswarapandian 5 years ago

    nice.