Question Detail

What least number should be added to 1056, so that the sum is completely divisible by 23

Answer: Option C

Explanation:

(1056 / 23) gives remainder 21

21 + 2 = 23, So we need to add 2

1. What is the largest 4 digit number exactly divisible by 88

9900
9999
9988
9944

Answer: Option D

Explanation:

Largest 4 digit number is 9999
After doing 9999 ÷ 88 we get remainder 55
Hence largest 4 digit number exactly divisible by 88 = 9999 - 55 = 9944

2. \begin{aligned}
46^2 - (?)^2 = 4398 - 3066
\end{aligned}

Answer: Option D

3. What least number must be subtracted from 427398 so that remaining number is divisible by 15

Answer: Option A

Explanation:

On dividing 427398 by 15 we get the remainder 3, so 3 should be subtracted

4. 1939392 * 625

1212120010
1212120000
1212120011
1212121010

Answer: Option B

Explanation:

Trick: when multiplying with \begin{aligned} 5^n
\end{aligned} then put n zeros to the right of multiplicand and divide the number with \begin{aligned} 2^n
\end{aligned}
So using this we can solve this question in much less
time.
\begin{aligned} 1939392 \times 5^4 = \frac {19393920000}{16} = 1212120000
\end{aligned}

5. For the integer n, if nnn is odd, then what is true

n is odd and n*n is even
n*n is odd
n is even
n*n is odd

Answer: Option A

Question Detail

What least number should be added to 1056, so that the sum is completely divisible by 23

1. What is the largest 4 digit number exactly divisible by 88

2. \begin{aligned} 46^2 - (?)^2 = 4398 - 3066 \end{aligned}

3. What least number must be subtracted from 427398 so that remaining number is divisible by 15

4. 1939392 * 625

5. For the integer n, if n*n*n is odd, then what is true

2. \begin{aligned}
46^2 - (?)^2 = 4398 - 3066
\end{aligned}

5. For the integer n, if nnn is odd, then what is true