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Direction Sense Test Questions Answers

  • 1. A man is facing west. He turns 45 degree in the clockwise direction and then another 180 degree in the same direction and then 270 degree in the anticlockwise direction. Find which direction he is facing now ?

    1. South-West
    2. West
    3. South
    4. East-South
    Answer And Explanation

    Answer: Option A

    Explanation:

    Please refer to the explanation image.
    The man firstly faces the direction OA. On moving 45 degree clockwise[Please check carefully always if clockwise or anticlockwise], he faces the direction OB.
    Now again he moved 180 degree clockwise, now he will be facing OC. From here he moved 270 degree anticlockwise, Finally he is facing OD, which is South west.

  • 2. A man is facing north. He turns 45 degree in the clockwise direction and then another 180 degree in the same direction and then 45 degree in the anticlockwise direction. Find which direction he is facing now ?

    1. North
    2. East
    3. West
    4. South
    Answer And Explanation

    Answer: Option D

    Explanation:

    Please refer to the explanation image.
    The man firstly faces the direction OA. On moving 45 degree clockwise, he faces the direction OB.
    Now again he moved 180 degree clockwise, now he will be facing OC. From here he moved 45 degree anticlockwise, Finally he is facing OD, which is South direction.

  • 3. One day, Raviraj left home and cycled 20 Km southwards, turned right and cycled 10 km and turned right and cycled 20 Km and turned left and cycled 20 Km. How many kilometres will he have to cycle to reach his home straight ?

    1. 50 Km
    2. 30 Km
    3. 40 Km
    4. 60 Km
    Answer And Explanation

    Answer: Option B

    Explanation:

    Please refer to explanation image,
    Raviraj starts from home at A, moves 20 Km in south upto B. Then he turns right and moves 10 Km upto C, then he turns right and moves 20 Km upto D, then he turns lefts and moves 20 Km upto E.

    So from image it is clear that, if he moves straight then he will have to move AD+DE, AD = BC = 10 Km
    So, he will have to move 10 + 20 = 30 Km

  • 4. A child is looking for his father. He went 90 meters in the east before turning to his right. He went 20 meters before turning to is right again to look for his father at his uncle's place 30 meters from this point. His father was not there. From there, he went 100 meters to his north before meeting his father in a street. How far did the son meet his father from starting point ?

    1. 80 metre
    2. 90 metre
    3. 100 metre
    4. 110 metre
    Answer And Explanation

    Answer: Option C

    Explanation:

    Clearly, the child moves from A to B 90 metres eastwards upto B, then turns right and moves 20 metre upto C, then turns right and moves upto 30 metre upto D. Finally he turns right and moves upto 100 metre upto E.

    So AB = 90 metre, BF = CD = 30 metre,
    So, AF = AB - BF = 60 metre

    Also DE = 100 metre, DF = BC = 20 metre
    So, EF = DE - DF = 80 metre

    as we can see in image that triangle AFE is a right angled triangle and we are having two sides, need to calculate third one, so we can apply Pythagoras theorem here

    \begin{aligned}
    A = AE = \sqrt{AF^2 + EF^2} \\
    = \sqrt{(60)^2+(80)^2} \\
    = \sqrt{3600+6400} \\
    = \sqrt{10000} = 100
    \end{aligned}

    So from starting point his father was 100 metre away.

  • 5. Kunal walks 10 km towards North. From there he walks 6 Km towards South. Then, he walks 3 Km towards east. How far and in which direction is he with reference to his starting point ?

    1. 5 Km North
    2. 5 Km South
    3. 5 Km East
    4. 5 Km North-East
    Answer And Explanation

    Answer: Option D

    Explanation:

    Clearly, Kunal moves from A 10 Km northwards upto B, then moves 6 Km southwards upto C, turns towards east and moves 3 km upto D.
    Then AC = (AB-BC) = 4 Km

    So Kunal distance from starting point A
    \begin{aligned}
    AD = \sqrt{AC^2 + CD^2} \\
    = \sqrt{4^2+3^2} \\
    = \sqrt{25} = 5
    \end{aligned}

    So AD is 5 Km also with reference to starting point Kunal's direction is North-East.

  • 6. Gaurav walks 20 metres towards North. He then turns left and walks 40 metres. He again turns left and walks 20 metres. Further, he moves 20 metres after turning to the right. How far is he from his original position ?

    1. 40 metres
    2. 50 metres
    3. 60 metres
    4. 70 metres
    Answer And Explanation

    Answer: Option C

    Explanation:

    Please check the movements of Gaurav in the figure.
    Now, Gaurav distance from his initial position A to E

    AE = (AD+DE) = 40 + 20 = 60 metres.

  • 7. A dog runs 20 metre towards East and turns Right, runs 10 metre and turns to right, runs 9 metre and again turns to left, runs 5 metre and then turns to left, runs 12 metre and finally turns to left and runs 6 metre. Now which direction dog is facing ?

    1. East
    2. North
    3. West
    4. South
    Answer And Explanation

    Answer: Option B

    Explanation:

    Now dog is facing North.

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