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Question Detail
Ten years ago A was half of B in age. If the ratio of their present ages is 3 : 4, what will be the total of their present ages
- 30
- 35
- 37
- 41
Answer: Option B
Explanation:
Let A's age 10 years ago = x years.
Then, B's age 10 years ago = 2x years.
(x + 10) / (2x+ lO) = 3/4
=> x = 5.
So, the total of their present ages =(x + 10 + 2x + 10)
= (3x + 20) = 35 years.
1. A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is
- 20 years
- 21 years
- 22 years
- 24 years
Answer: Option C
Explanation:
Let the son's present age be x years. Then, man's present age = (x + 24) years
=> (x + 24) + 2 = 2(x + 2)
=> x + 26 = 2x + 4
So, x = 22
2. The total age of A and B is 12 years more than the total age of B and C. C is how many year younger than A
- 11
- 12
- 13
- 14
Answer: Option B
Explanation:
Given that A+B = 12 + B + C
=> A – C = 12 + B – B = 12
=> C is younger than A by 12 years
3. The ages of two persons differ by 16 years. 6 years ago, the elder one was 3 times as old as the younger one. What are their present ages of the elder person
- 15
- 20
- 25
- 30
Answer: Option D
Explanation:
Let's take the present age of the elder person = x
and the present age of the younger person = x – 16
(x – 6) = 3 (x-16-6)
=> x – 6 = 3x – 66
=> 2x = 60
=> x = 60/2 = 30
4. Average age of A and B is 24 years and average age of B, C and D is 22 years. The sum of the ages of A, B, C and D is
- 90
- 98
- 120
- Data is not adequate
Answer: Option D
5. The ages of two persons differ by 20 years. If 5 years ago, the elder one be 5 times as old as the younger one, their present ages (in years) are respectively
- 20,20
- 20,10
- 25,15
- 30,10
Answer: Option D
Explanation:
Let their ages be x and (x + 20) years.
5 (x - 5) = (x + 20 - 5) or 4x = 40 or x = 10.
Their present ages are 30 years and 10 years
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