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Question Detail
A car moves at 80 km/hr. What is the speed of the car in meters per second ?
- \begin{aligned} 20\frac{2}{9} m\sec \end{aligned}
- \begin{aligned} 22\frac{2}{9} m\sec \end{aligned}
- \begin{aligned} 24\frac{2}{9} m\sec \end{aligned}
- \begin{aligned} 26\frac{2}{9} m\sec \end{aligned}
Answer: Option B
Explanation:
\begin{aligned}
Speed = \left(80*\frac{5}{18}\right) m/sec \\
= \frac{200}{9} m/sec \\
= 22\frac{2}{9} m\sec
\end{aligned}
1. A car moves at 80 km/hr. What is the speed of the car in meters per second ?
- \begin{aligned} 20\frac{2}{9} m\sec \end{aligned}
- \begin{aligned} 22\frac{2}{9} m\sec \end{aligned}
- \begin{aligned} 24\frac{2}{9} m\sec \end{aligned}
- \begin{aligned} 26\frac{2}{9} m\sec \end{aligned}
Answer: Option B
Explanation:
\begin{aligned}
Speed = \left(80*\frac{5}{18}\right) m/sec \\
= \frac{200}{9} m/sec \\
= 22\frac{2}{9} m\sec
\end{aligned}
2. In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. What is the duration of the flight ?
- 3 hours
- 2.4 hours
- 1.4 hours
- 1 hour
Answer: Option D
Explanation:
Let the duration of the flight be x hours.
Then
\begin{aligned}
\frac{600}{x}-\frac{600}{x + \frac{1}{2}} = 200 \\
\frac{600}{x}-\frac{1200}{2x+1} = 200 \\
x(2x+1) = 3 \\
2x^2 + x - 3 = 0 \\
=> (2x+3)(x-1)=0
\end{aligned}
Neglecting the negative value for x we get x = 1
3. Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour ?
- 8 minutes
- 10 mintues
- 12 minutes
- 14 minutes
Answer: Option B
Explanation:
Due to stoppages, it covers 9 km less.
Time taken to cover 9 km = (9/54) hour
= (1/6)*60 minutes
= 10 minutes
4. Two boys starting from the same place walk at a rate of 5kmph and 5.5kmph respectively. What time will they take to be 8.5km apart, if they walk in the same direction?
- 15 hours
- 16 hours
- 17 hours
- 18 hours
Answer: Option C
Explanation:
In this type of questions we need to get the relative speed between them,
The relative speed of the boys = 5.5kmph – 5kmph
= 0.5 kmph
Distance between them is 8.5 km
Time = Distance/Speed
Time= 8.5km / 0.5 kmph = 17 hrs
5. The distance between two cities A and B is 330 Km. A train starts from A at 8 a.m. and travel towards B at 60 km/hr. Another train starts from B at 9 a.m and travels towards A at 75 Km/hr. At what time do they meet?
- 10 am
- 11 am
- 12 pm
- 1 pm
Answer: Option B
Explanation:
Suppose they meet x hrs after 8 a.m.
then
(Distance moved by first in x hrs) + [Distance moved by second in (x-1) hrs]
= 330
So, 60x+75(x-1) = 330
x=3.
So,they meet at (8+3). i.e 11a.m.
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