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Question Detail
A man's speed with the current is 20 kmph and speed of the current is 3 kmph. The Man's speed against the current will be
- 11 kmph
- 12 kmph
- 14 kmph
- 17 kmph
Answer: Option C
Explanation:
If you solved this question yourself, then trust me you have a all very clear with the basics of this chapter.
If not then lets solve this together.
Speed with current is 20,
speed of the man + It is speed of the current
Speed in still water = 20 - 3 = 17
Now speed against the current will be
speed of the man - speed of the current
= 17 - 3 = 14 kmph
1. Sahil can row 3 km against the stream in 20 minutes and he can return in 18 minutes. What is rate of current ?
- 1/2 km/hr
- 1/3 km/hr
- 2 km/hr
- 4 km/hr
Answer: Option A
Explanation:
\begin{aligned}
\text{Speed Upstream} = \frac{3}{\frac{20}{60}} = 9 km/hr \\
\text{Speed Downstream} = \frac{3}{\frac{18}{60}} = 10 km/hr \\
\text{Rate of current will be} \\
\frac{10-9}{2} = \frac{1}{2} km/hr
\end{aligned}
2. A man can row at 5 kmph in still water. If the velocity of the current is 1 kmph and it takes him 1 hour to row to a place and come back. how far is that place.
- .4 km
- 1.4 km
- 2.4 km
- 3.4 km
Answer: Option C
Explanation:
Let the distance is x km
Rate downstream = 5 + 1 = 6 kmph
Rate upstream = 5 - 1 = 4 kmph
then
x/6 + x/4 = 1 [because distance/speed = time]
=> 2x + 3x = 12
=> x = 12/5 = 2.4 km
3. A man can row upstream 10 kmph and downstream 20 kmph. Find the man rate in still water and rate of the stream.
- 0,5
- 5,5
- 15,5
- 10,5
Answer: Option C
Explanation:
Please remember,
If a is rate downstream and b is rate upstream
Rate in still water = 1/2(a+b)
Rate of current = 1/2(a-b)
=> Rate in still water = 1/2(20+10) = 15 kmph
=> Rate of current = 1/2(20-10) = 5 kmph
4. A man takes twice as long to row a distance against the stream as to row the same distance in favour of the stream. The ratio of the speed of the boat in still water and stream is
- 3:1
- 1:3
- 2:4
- 4:2
Answer: Option A
Explanation:
Let speed downstream = x kmph
Then Speed upstream = 2x kmph
So ratio will be,
(2x+x)/2 : (2x-x)/2
=> 3x/2 : x/2 => 3:1
5. A man rows 750 m in 675 seconds against the stream and returns in 7 and half minutes. His rowing speed in still water is
- 4 kmph
- 5 kmph
- 6 kmph
- 7 kmph
Answer: Option B
Explanation:
Rate upstream = (750/675) = 10/9 m/sec
Rate downstream (750/450) m/sec = 5/3 m/sec
Rate in still water = (1/2)*[(10/9) + (5/3)] m/sec.
= 25/18 m/sec
= (25/18)*(18/5) kmph
= 5 kmph
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