Question Detail
A shopkeeper sells a transistor at Rs. 840 at a gain of 20% and another for Rs. 960 at the loss of 4%. Find his total gain percent.
- \begin{aligned} 5\frac{12}{17}\% \end{aligned}
- \begin{aligned} 5\frac{13}{17}\% \end{aligned}
- \begin{aligned} 5\frac{14}{17}\% \end{aligned}
- \begin{aligned} 5\frac{15}{17}\% \end{aligned}
Answer: Option D
Explanation:
In this type of question, we will first find total C.P. of items, then total S.P. of items, then we will get gain or loss. From which we can easily calculate its percentage.
So lets solve it now.
\begin{aligned}
\text{So, C.P. of 1st transistor = }\\
\left( \frac{100}{120} * 840 \right) = 700 \\
\text{C.P. of 2nd transistor = }\\
\left( \frac{100}{96} * 960 \right) = 1000 \\
\text{Total C.P. = 1700 }\\
\text{Total S.P. = 1800 }\\
\text{Gain = 1800 - 1700 = 100}\\
\text{Gain% = } \left( \frac{100}{1700} * 100 \right) \\
= 5\frac{15}{17}\%
\end{aligned}
-
ashwini 12 years ago
plz explain how 1700,1800 came
mastguru 12 years ago replied
Hello Ashwini Ji,
Total C.P. is 1700,
i.e. C.P. of first + C.P. of second
= 700 + 1000 = 1700 (which we calculated in first lines)Total S.P. is 1800, it is given in question..
i.e. 840 + 960 = 1800 -
ashwini 12 years ago
how 1700 and 1800 got
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