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Question Detail
A train covers a distance in 50 minutes, if it runs at a speed of 48kmph on an average. Find the speed at which the train must run to reduce the time of journey to 40 minutes.
- 50 km/hr
- 60 km/hr
- 65 km/hr
- 70 km/hr
Answer: Option B
Explanation:
We are having time and speed given, so first we will calculate the distance. Then we can get new speed for given time and distance.
Lets solve it.
Time = 50/60 hr = 5/6 hr
Speed = 48 mph
Distance = S*T = 48 * 5/6 = 40 km
New time will be 40 minutes so,
Time = 40/60 hr = 2/3 hr
Now we know,
Speed = Distance/Time
New speed = 40*3/2 kmph = 60kmph
1. A man in a train notices that he can count 41 telephone posts in one minute. If they are known to be 50 metres apart, then at what speed is the train travelling?
- 60 km/hr
- 100 km/hr
- 110 km/hr
- 120 km/hr
Answer: Option D
Explanation:
Number of gaps between 41 poles = 40
So total distance between 41 poles = 40*50
= 2000 meter = 2 km
In 1 minute train is moving 2 km/minute.
Speed in hour = 2*60 = 120 km/hour
2. A walks around a circular field at the rate of one round per hour while B runs around it at the rate of six rounds per hour. They start at same point at 7:30 am. They shall first cross each other at ?
- 7:15 am
- 7:30 am
- 7: 42 am
- 7:50 am
Answer: Option C
Explanation:
Relative speed between two = 6-1 = 5 round per hour
They will cross when one round will complete with relative speed,
which is 1/5 hour = 12 mins.
So 7:30 + 12 mins = 7:42
3. Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour ?
- 8 minutes
- 10 mintues
- 12 minutes
- 14 minutes
Answer: Option B
Explanation:
Due to stoppages, it covers 9 km less.
Time taken to cover 9 km = (9/54) hour
= (1/6)*60 minutes
= 10 minutes
4. A person travels equal distances with speed of 3 km/hr, 4 km/hr and 5 km/hr and takes a total of 47 minutes. Find the total distane
- 3 km
- 4 km
- 6 km
- 9 km
Answer: Option A
Explanation:
Let the distance be 3x km,
then,
x3+x4+x5=476047x60=4760x=1
So total distance = 3*1 = 3 Km
5. How many minutes does Aditya take to cover a distance of 400 m, if he runs at a speed of 20 km/hr
- 115min
- 215min
- 315min
- 415min
Answer: Option A
Explanation:
We know that,
Time=DistanceSpeedSpeed=20 km/hr=20∗518m/sec=509m/sec Time =(400∗950)=72sec=115min
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