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Question Detail
An electronic device makes a beep after every 60 sec. Another device makes a beep after every 62 sec. They beeped together at 10 a.m. The time when they will next make a beep together at the earliest, is
- 10:28 am
- 10:30 am
- 10:31 am
- None of above
Answer: Option C
Explanation:
L.C.M. of 60 and 62 seconds is 1860 seconds
1860/60 = 31 minutes
They will beep together at 10:31 a.m.
Sometimes questions on red lights blinking comes in exam, which can be solved in the same way
1. Reduce \begin{aligned}
\frac{368}{575}
\end{aligned} to the lowest terms.
- \begin{aligned} \frac{30}{25} \end{aligned}
- \begin{aligned} \frac{28}{29} \end{aligned}
- \begin{aligned} \frac{28}{29} \end{aligned}
- \begin{aligned} \frac{16}{25} \end{aligned}
Answer: Option D
Explanation:
We can do it easily by in two steps
Step1: We get the HCF of 368 and 575 which is 23
Step2: Divide both by 23, we will get the answer 16/25
2. LCM of two numbers is 7700 and HCF is 11. If one number is 308 then other number is
- 269
- 285
- 300
- 275
Answer: Option D
3. What will be the LCM of 8, 24, 36 and 54
- 54
- 108
- 216
- 432
Answer: Option C
Explanation:
LCM of 8-24-36-54 will be
2*2*2*3*3*3 = 216
4. The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. is
- 48
- 22
- 56
- 27
Answer: Option A
Explanation:
Let the numbers be 3x and 4x. Then, their H.C.F. = x. So, x = 4.
So, the numbers 12 and 16.
L.C.M. of 12 and 16 = 48.
5. If the product of two numbers is 84942 and their H.C.F. is 33, find their L.C.M.
- 2574
- 2500
- 1365
- 1574
Answer: Option A
Explanation:
HCF * LCM = 84942, because we know
Product of two numbers = Product of HCF and LCM
LCM = 84942/33 = 2574
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