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Question Detail
At the end of a business conference the ten people present all shake hands with each other once. How many handshakes will there be altogether ?
- 20
- 45
- 55
- 90
Answer: Option B
Explanation:
Total number of handshakes =
9+8+7+6+5+4+3+2+1 = 45
1. In a caravan, in addition to 50 hens, there are 45 goats and 8 camels with some keepers. If the total number of feet be 224 more than the number of heads in the caravan, the number of keepers is
- 5
- 8
- 10
- 15
Answer: Option D
Explanation:
Let the number of keepers be x.
Then, total number of feet = 2*50+4*45+4*8+2x
= 2x + 312
Total number of heads = 50+45+8+x = 103 + x
Now, (2x+312) = (103+x)+224
=> x = 15
2. Find the least number which leaves a reminder of 3 when divided by 5, 6, 7 and 8, but leaves no reminder when divided by 9 ?
- 1683
- 1692
- 1598
- 1458
Answer: Option A
Explanation:
First of all, calculate LCM of 5, 6, 7 and 8 which is 840.
Suppose Number is K
then 840 * K + 3 is divisible by 9.
If K = 1, number = (840 × 1) + 3 = 843 which is not divisible by 9
If K = 2, number = (840 × 2) + 3 = 1683 which is divisible by 9
So 1683 is correct answer.
3. Reena is twice as old as Sunita. Three years ago, she was three times as old as Sunita. How old is Reena now ?
- 6 years
- 12 years
- 14 years
- 16 years
Answer: Option B
Explanation:
Let Sunita's present age = x years
Then Reena present age = 2x years
Three years ago
(2x-3) = 3(x-3)
2x - 3 = 3x - 9
or x = 6
Reena age = 2x = 2*6 = 12 year.
4. If 100 cats kill 100 mice in 100 days, then 4 cats would kill 4 mice in how many days ?
- 4 day
- 10 day
- 40 day
- 100 day
Answer: Option D
5. A is three times as old as B. C was twice-as old as A four years ago. In four years' time, A will be 31. What are the present ages of B and C ?
- 9, 46
- 9, 50
- 10, 46
- 10, 50
Answer: Option B
Explanation:
As from the question we have,
A = 3B --- (i)
c - 4 = 2(A+4) ---(ii)
Also, A + 4 = 31
or A = 31-4 = 27
Putting A = 27 in (i) we get
B = 9
Putting A = 27 in (ii) we get
C = 50
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