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Question Detail
Find the average of first 10 multiples of 7
- 35.5
- 37.5
- 38.5
- 40.5
Answer: Option C
Explanation:
\begin{aligned}
= \frac {7(1+2+3+...+10)}{10}
\end{aligned}
\begin{aligned}
= \frac {7(10(10+1))}{10 \times 2}
\end{aligned}
\begin{aligned}
= \frac {7(110)}{10 \times 2} = 38.5
\end{aligned}
1. Average of 10 matches is 32, How many runs one should should score to increase his average by 4 runs.
- 70
- 76
- 78
- 80
Answer: Option B
Explanation:
Average after 11 innings should be 36
So, Required score = (11 * 36) - (10 * 32)
= 396 - 320 = 76
2. Find the average of first 10 multiples of 7
- 35.5
- 37.5
- 38.5
- 40.5
Answer: Option C
Explanation:
\begin{aligned}
= \frac {7(1+2+3+...+10)}{10}
\end{aligned}
\begin{aligned}
= \frac {7(10(10+1))}{10 \times 2}
\end{aligned}
\begin{aligned}
= \frac {7(110)}{10 \times 2} = 38.5
\end{aligned}
3. Average of 10 numbers is zero. At most how many numbers may be greater than zero
- 0
- 1
- 5
- 9
Answer: Option D
4. Average of five numbers is 27. If one number is excluded the average becomes 25. The excluded number is
- 35
- 45
- 55
- 65
Answer: Option A
Explanation:
Number is (5*27) - (4*25) = 135-100 = 35
5. Average of first five multiples of 3 is
- 9
- 11
- 13
- 15
Answer: Option A
Explanation:
\begin{aligned}
Average = \frac{3(1+2+3+4+5)}{5} = \frac{45}{5} = 9
\end{aligned}
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