Question Detail

Find the greatest number that will divide 400, 435 and 541 leaving 9, 10 and 14 as remainders respectively

Answer: Option B

Explanation:

Answer will be HCF of (400-9, 435-10, 541-14)

HCF of (391, 425, 527) = 17

1. Reduce \begin{aligned}
\frac{368}{575}
\end{aligned} to the lowest terms.

\begin{aligned} \frac{30}{25} \end{aligned}
\begin{aligned} \frac{28}{29} \end{aligned}
\begin{aligned} \frac{28}{29} \end{aligned}
\begin{aligned} \frac{16}{25} \end{aligned}

Answer: Option D

Explanation:

We can do it easily by in two steps
Step1: We get the HCF of 368 and 575 which is 23
Step2: Divide both by 23, we will get the answer 16/25

2. Find the HCF of
\begin{aligned}
2^2 \times 3^2 \times 7^2, 2 \times 3^4 \times 7
\end{aligned}

Answer: Option B

Explanation:

HCF is Highest common factor, so we need to get the common highest factors among given values. So we got
2 * 3*3 * 7

3. Find the largest number of four digits which is exactly divisible by 27,18,12,15

9700
9710
9720
9730

Answer: Option C

Explanation:

LCM of 27-18-12-15 is 540.
After dividing 9999 by 540 we get 279 remainder.
So answer will be 9999-279 = 9720

4. Six bells commence tolling together and toll at the intervals of 2,4,6,8,10,12 seconds resp. In 60 minutes how many times they will toll together.

Answer: Option D

Explanation:

LCM of 2-4-6-8-10-12 is 120 seconds, that is 2 minutes.

Now 60/2 = 30
Adding one bell at the starting it will 30+1 = 31

5. Find the largest number which divides 62,132,237 to leave the same reminder

Answer: Option C

Explanation:

Trick is HCF of (237-132), (132-62), (237-62)
= HCF of (70,105,175) = 35

Question Detail

Find the greatest number that will divide 400, 435 and 541 leaving 9, 10 and 14 as remainders respectively

1. Reduce \begin{aligned}
\frac{368}{575}
\end{aligned} to the lowest terms.

2. Find the HCF of
\begin{aligned}
2^2 \times 3^2 \times 7^2, 2 \times 3^4 \times 7
\end{aligned}

3. Find the largest number of four digits which is exactly divisible by 27,18,12,15

4. Six bells commence tolling together and toll at the intervals of 2,4,6,8,10,12 seconds resp. In 60 minutes how many times they will toll together.

5. Find the largest number which divides 62,132,237 to leave the same reminder

Thanks ! Your comment will be approved shortly !

Videos @mastguru

To Appreciate Our Effort, Please Like Us

Quantitative Aptitude

English Aptitude

Reasoning Aptitude

Computer Awareness

General Knowledge

Current Affairs

IT Officer Aptitude

Programming Aptitude

Latest Govt Jobs

Question Detail

Find the greatest number that will divide 400, 435 and 541 leaving 9, 10 and 14 as remainders respectively

1. Reduce \begin{aligned} \frac{368}{575} \end{aligned} to the lowest terms.

2. Find the HCF of \begin{aligned} 2^2 \times 3^2 \times 7^2, 2 \times 3^4 \times 7 \end{aligned}

3. Find the largest number of four digits which is exactly divisible by 27,18,12,15

4. Six bells commence tolling together and toll at the intervals of 2,4,6,8,10,12 seconds resp. In 60 minutes how many times they will toll together.

5. Find the largest number which divides 62,132,237 to leave the same reminder

Thanks ! Your comment will be approved shortly !

Videos @mastguru

To Appreciate Our Effort, Please Like Us

Current Affairs

Govt Jobs

Current Affairs 15th August 2019

Current Affairs 14th August 2019

Current Affairs 13th August 2019

Current Affairs 12th August 2019

Current Affairs 11th August 2019

Junior Associates (Clerical Cadre) Jobs in SBI

Technical Jobs in NGRI

Experienced Personnel Jobs in Power Grid NRTS-I

The Punjab State Transmission Corporation Limited (PSTCL) Jobs

Energy Assistant Jobs in AP CPDCL

1. Reduce \begin{aligned}
\frac{368}{575}
\end{aligned} to the lowest terms.

2. Find the HCF of
\begin{aligned}
2^2 \times 3^2 \times 7^2, 2 \times 3^4 \times 7
\end{aligned}