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Question Detail
Find the greatest number which on dividing 1661 and 2045, leaves a reminder of 10 and 13 respectively
- 125
- 127
- 129
- 131
Answer: Option B
Explanation:
In this type of question, its obvious we need to calculate the HCF, trick is
HCF of (1661 - 10) and (2045 -13)
= HCF (1651, 2032) = 127
1. Find the greatest number which on dividing 1661 and 2045, leaves a reminder of 10 and 13 respectively
- 125
- 127
- 129
- 131
Answer: Option B
Explanation:
In this type of question, its obvious we need to calculate the HCF, trick is
HCF of (1661 - 10) and (2045 -13)
= HCF (1651, 2032) = 127
2. If LCM of two number is 693, HCF of two numbers is 11 and one number is 99, then find other
- 34
- 77
- 12
- 45
Answer: Option B
Explanation:
For any this type of question, remember
Product of two numbers = Product of their HCF and LCM
So Other number = \begin{aligned} \frac{693 \times 11}{99} \end{aligned} = 77
3. If the product of two numbers is 84942 and their H.C.F. is 33, find their L.C.M.
- 2574
- 2500
- 1365
- 1574
Answer: Option A
Explanation:
HCF * LCM = 84942, because we know
Product of two numbers = Product of HCF and LCM
LCM = 84942/33 = 2574
4. What will be the LCM of 8, 24, 36 and 54
- 54
- 108
- 216
- 432
Answer: Option C
Explanation:
LCM of 8-24-36-54 will be
2*2*2*3*3*3 = 216
5. Find the HCF of 54, 288, 360
- 18
- 36
- 54
- 108
Answer: Option A
Explanation:
Lets solve this question by factorization method.
\begin{aligned}
18 = 2 \times 3^2, 288 = 2^5 \times 3^2, 360 = 2^3 \times 3^2 \times 5
\end{aligned}
So HCF will be minimum term present in all three, i.e.
\begin{aligned}
2 \times 3^2 = 18
\end{aligned}
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