Question Detail

Find the HCF of 54, 288, 360

Answer: Option A

Explanation:

Lets solve this question by factorization method.

$\begin{aligned} 18 = 2 \times 3^2, 288 = 2^5 \times 3^2, 360 = 2^3 \times 3^2 \times 5 \end{aligned}$

So HCF will be minimum term present in all three, i.e.

$\begin{aligned} 2 \times 3^2 = 18 \end{aligned}$

1. Find the HCF of $\begin{aligned} \frac{2}{3}, \frac{4}{6}, \frac{8}{27} \end{aligned}$

$\begin{aligned} \frac{2}{27} \end{aligned}$
$\begin{aligned} \frac{8}{3} \end{aligned}$
$\begin{aligned} \frac{2}{3} \end{aligned}$
$\begin{aligned} \frac{8}{27} \end{aligned}$

Answer: Option A

Explanation:

Whenever we have to solve this sort of question, remember the formula.
HCF =

$\begin{aligned} \frac{HCF of Numerators}{LCM of Denominators} \end{aligned}$
So answers will be option 1

2. An electronic device makes a beep after every 60 sec. Another device makes a beep after every 62 sec. They beeped together at 10 a.m. The time when they will next make a beep together at the earliest, is

10:28 am
10:30 am
10:31 am
None of above

Answer: Option C

Explanation:

L.C.M. of 60 and 62 seconds is 1860 seconds
1860/60 = 31 minutes

They will beep together at 10:31 a.m.

Sometimes questions on red lights blinking comes in exam, which can be solved in the same way

3. Find the HCF of 54, 288, 360

Answer: Option A

Explanation:

Lets solve this question by factorization method.

$\begin{aligned} 18 = 2 \times 3^2, 288 = 2^5 \times 3^2, 360 = 2^3 \times 3^2 \times 5 \end{aligned}$

So HCF will be minimum term present in all three, i.e.

$\begin{aligned} 2 \times 3^2 = 18 \end{aligned}$

4. Find the greatest number that will divide 400, 435 and 541 leaving 9, 10 and 14 as remainders respectively

Answer: Option B

Explanation:

Answer will be HCF of (400-9, 435-10, 541-14)

HCF of (391, 425, 527) = 17

5. The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. is

Answer: Option A

Explanation:

Let the numbers be 3x and 4x. Then, their H.C.F. = x. So, x = 4.
So, the numbers 12 and 16.
L.C.M. of 12 and 16 = 48.

Question Detail

Find the HCF of 54, 288, 360

1. Find the HCF of $\begin{aligned} \frac{2}{3}, \frac{4}{6}, \frac{8}{27} \end{aligned}$

2. An electronic device makes a beep after every 60 sec. Another device makes a beep after every 62 sec. They beeped together at 10 a.m. The time when they will next make a beep together at the earliest, is

3. Find the HCF of 54, 288, 360

4. Find the greatest number that will divide 400, 435 and 541 leaving 9, 10 and 14 as remainders respectively

5. The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. is

Thanks ! Your comment will be approved shortly !

Videos @mastguru

To Appreciate Our Effort, Please Like Us

Quantitative Aptitude

English Aptitude

Reasoning Aptitude

Computer Awareness

General Knowledge

Current Affairs

IT Officer Aptitude

Programming Aptitude

Latest Govt Jobs

Question Detail

Find the HCF of 54, 288, 360

1. Find the HCF of 23,46,827\begin{aligned} \frac{2}{3}, \frac{4}{6}, \frac{8}{27} \end{aligned}

2. An electronic device makes a beep after every 60 sec. Another device makes a beep after every 62 sec. They beeped together at 10 a.m. The time when they will next make a beep together at the earliest, is

3. Find the HCF of 54, 288, 360

4. Find the greatest number that will divide 400, 435 and 541 leaving 9, 10 and 14 as remainders respectively

5. The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. is

Thanks ! Your comment will be approved shortly !

Videos @mastguru

To Appreciate Our Effort, Please Like Us

Current Affairs

Govt Jobs

Current Affairs 15th August 2019

Current Affairs 14th August 2019

Current Affairs 13th August 2019

Current Affairs 12th August 2019

Current Affairs 11th August 2019

Junior Associates (Clerical Cadre) Jobs in SBI

Technical Jobs in NGRI

Experienced Personnel Jobs in Power Grid NRTS-I

The Punjab State Transmission Corporation Limited (PSTCL) Jobs

Energy Assistant Jobs in AP CPDCL

1. Find the HCF of $\begin{aligned} \frac{2}{3}, \frac{4}{6}, \frac{8}{27} \end{aligned}$