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Question Detail
Find the least number which leaves a reminder of 3 when divided by 5, 6, 7 and 8, but leaves no reminder when divided by 9 ?
 1683
 1692
 1598
 1458
Answer: Option A
Explanation:
First of all, calculate LCM of 5, 6, 7 and 8 which is 840.
Suppose Number is K
then 840 * K + 3 is divisible by 9.
If K = 1, number = (840 × 1) + 3 = 843 which is not divisible by 9
If K = 2, number = (840 × 2) + 3 = 1683 which is divisible by 9
So 1683 is correct answer.
1. A is three times as old as B. C was twiceas old as A four years ago. In four years' time, A will be 31. What are the present ages of B and C ?
 9, 46
 9, 50
 10, 46
 10, 50
Answer: Option B
Explanation:
As from the question we have,
A = 3B  (i)
c  4 = 2(A+4) (ii)
Also, A + 4 = 31
or A = 314 = 27
Putting A = 27 in (i) we get
B = 9
Putting A = 27 in (ii) we get
C = 50
2. The number of boys in a class is three times the number of girls. Which one of the following numbers cannot represent the total number of children in the class ?
 48
 44
 42
 40
Answer: Option C
Explanation:
Let number of girls = x and number of boys = 3x.
Then, 3x + x = 4x = total number of students.
Thus, to find exact value of x, the total number of students must be divisible by 4.
3. A certain number of horses and an equal number of men are going somewhere. Half of the owners are on their horses' back while the remaining ones are walking along leading their horses. If the number of legs walking on the ground is 70, how many horses are there ?
 8
 10
 12
 14
Answer: Option D
Explanation:
Let number of horses = number of men = x.
Then, number of legs = 4x + 2 x (x/2) = 5x.
So, 5X = 70 or x = 14.
4. In a class, there are 18 boys who are over 160 cm tall. If these constitute threefourths of the boys and the total number of boys is twothirds of the total number of students in the class, what is the number of girls in the class ?
 10
 12
 14
 18
Answer: Option B
Explanation:
Let the number of boys be x.
Then, 3/4 x = 18
=> x = 24
If total number of students is y, then
2/3 y = 24
=> y = 36
Number of girls in class = y  x
= 36  24 = 12
5. A student got twice as many sums wrong as he got right. If he attempted 48 sums in all, how many did he solve correctly ?
 12
 16
 24
 18
Answer: Option B
Explanation:
Suppose boy got x sums right and 2x sums wrong,
then,
x+2x = 48
=> 3x = 48
=> x = 16
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