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Question Detail
Find the least number which leaves a reminder of 3 when divided by 5, 6, 7 and 8, but leaves no reminder when divided by 9 ?
 1683
 1692
 1598
 1458
Answer: Option A
Explanation:
First of all, calculate LCM of 5, 6, 7 and 8 which is 840.
Suppose Number is K
then 840 * K + 3 is divisible by 9.
If K = 1, number = (840 × 1) + 3 = 843 which is not divisible by 9
If K = 2, number = (840 × 2) + 3 = 1683 which is divisible by 9
So 1683 is correct answer.
1. The number of boys in a class is three times the number of girls. Which one of the following numbers cannot represent the total number of children in the class ?
 48
 44
 42
 40
Answer: Option C
Explanation:
Let number of girls = x and number of boys = 3x.
Then, 3x + x = 4x = total number of students.
Thus, to find exact value of x, the total number of students must be divisible by 4.
2. A certain number of horses and an equal number of men are going somewhere. Half of the owners are on their horses' back while the remaining ones are walking along leading their horses. If the number of legs walking on the ground is 70, how many horses are there ?
 8
 10
 12
 14
Answer: Option D
Explanation:
Let number of horses = number of men = x.
Then, number of legs = 4x + 2 x (x/2) = 5x.
So, 5X = 70 or x = 14.
3. Reena is twice as old as Sunita. Three years ago, she was three times as old as Sunita. How old is Reena now ?
 6 years
 12 years
 14 years
 16 years
Answer: Option B
Explanation:
Let Sunita's present age = x years
Then Reena present age = 2x years
Three years ago
(2x3) = 3(x3)
2x  3 = 3x  9
or x = 6
Reena age = 2x = 2*6 = 12 year.
4. First bunch of bananas has (1/4) again as many bananas as a second bunch. If the second bunch has 3 bananas less than the first bunch, then the number of bananas in the first bunch are
 9
 10
 12
 15
Answer: Option D
Explanation:
Let the number of bananas in the second bunch be x.
Then, the number of bananas in the first bunch
= x + 1/4 x
= 5/4 x
So,
5/4 x  x = 3
=> 5x  4x = 12
x = 12
Number of bananas in first bunch
= 5/4 * 12 = 15
5. A is three times as old as B. C was twiceas old as A four years ago. In four years' time, A will be 31. What are the present ages of B and C ?
 9, 46
 9, 50
 10, 46
 10, 50
Answer: Option B
Explanation:
As from the question we have,
A = 3B  (i)
c  4 = 2(A+4) (ii)
Also, A + 4 = 31
or A = 314 = 27
Putting A = 27 in (i) we get
B = 9
Putting A = 27 in (ii) we get
C = 50
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