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HCF of
\begin{aligned}
2^2 \times 3^2 \times 5^2, 2^4 \times 3^4 \times 5^3 \times 11
\end{aligned} is

  • \begin{aligned} 2^4 \times 3^4 \times 5^3 \end{aligned}
  • \begin{aligned} 2^4 \times 3^4 \times 5^3 \times 11 \end{aligned}
  • \begin{aligned} 2^2 \times 3^2 \times 5^2 \end{aligned}
  • \begin{aligned} 2 \times 3 \times 5 \end{aligned}
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2. HCF of
\begin{aligned}
2^2 \times 3^2 \times 5^2, 2^4 \times 3^4 \times 5^3 \times 11
\end{aligned} is

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  • \begin{aligned} 2^4 \times 3^4 \times 5^3 \times 11 \end{aligned}
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  • \begin{aligned} 2 \times 3 \times 5 \end{aligned}

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  • babu 12 years ago

    in ques. no 1 we have taken the extra no. ie. 7, then why not 11 in this question?