Question Detail

if a = 0.1039, then the value of
\begin{aligned} \sqrt{4a^2 - 4a + 1} + 3a \end{aligned}

12.039
1.2039
11.039
1.1039

Answer: Option D

Explanation:

Tip: Please check the question carefully before answering. As 3a is not under the root we can convert it into a formula , lets evaluate now :

\begin{aligned}
= \sqrt{4a^2 - 4a + 1} + 3a \end{aligned}

\begin{aligned}
= \sqrt{(1)^2 + (2a)^2 - 2x1x2a} + 3a \end{aligned}

\begin{aligned}
= \sqrt{(1-2a)^2} + 3a \end{aligned}

\begin{aligned}
= (1-2a) + 3a \end{aligned}

\begin{aligned}
= (1-2a) + 3a \end{aligned}

\begin{aligned}
= 1 + a = 1 + 0.1039 = 1.1039 \end{aligned}

1. Evaluate
\begin{aligned}
\sqrt{53824}
\end{aligned}

Answer: Option B

2. Evaluate
\begin{aligned}
\sqrt{1\frac{9}{16}}
\end{aligned}

\begin{aligned} 1\frac{1}{6} \end{aligned}
\begin{aligned} 1\frac{1}{5} \end{aligned}
\begin{aligned} 1\frac{1}{4} \end{aligned}
\begin{aligned} 1\frac{1}{3} \end{aligned}

Answer: Option C

Explanation:

\begin{aligned}
= \sqrt{\frac{25}{16}}
\end{aligned}

\begin{aligned}
= \frac{\sqrt{25}}{\sqrt{16}}
\end{aligned}

\begin{aligned}
= \frac{5}{4}
\end{aligned}

\begin{aligned}
= 1\frac{1}{4}
\end{aligned}

3. Evaluate
\begin{aligned}
\sqrt{248+\sqrt{64}}
\end{aligned}

Answer: Option C

Explanation:

\begin{aligned}
= \sqrt{248+\sqrt{64}}
\end{aligned}

\begin{aligned}
= \sqrt{248+8}
\end{aligned}

\begin{aligned}
= \sqrt{256}
\end{aligned}

\begin{aligned}
= 16
\end{aligned}

4. What is the smallest number by which 3600 be divided to make it a perfect cube.

Answer: Option A

Explanation:

\begin{aligned}
3600 = 2^3 \times 5^2 \times 3^2 \times 2
\end{aligned}
To make it a perfect cube it must be divided by
\begin{aligned}
5^2 \times 3^2 \times 2 = 450
\end{aligned}