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Question Detail
In 10 years, A will be twice as old5as B was 10 years ago. If A is now 9 years older than B, the present age of B is
- 35
- 37
- 39
- 41
Answer: Option C
Explanation:
Let B's age = x years.
Then, As age = (x+ 9) years.
(x+9+10)=2(x—10)
hence x=39.
Present age of B = 39 years
1. Ratio of ages of three persons is 4:7:9, Eight years ago, the sum of their ages was 56. Find their present ages.
- 16,35,36
- 12,28,36
- 16,28,27
- 16,28,36
Answer: Option D
Explanation:
Let the present ages are 4x, 7x, 9x.
=> (4x-8) + (7x-8) + (9x-8) = 56
=> 20x = 80
=> x = 4
So their present ages are: 16,28,36
2. Average age of A and B is 24 years and average age of B, C and D is 22 years. The sum of the ages of A, B, C and D is
- 90
- 98
- 120
- Data is not adequate
Answer: Option D
3. Sachin is younger than Rahul by 7 years. If the ratio of their ages is 7:9, find the age of Sachin
- 23.5
- 24.5
- 12.5
- 14.5
Answer: Option B
Explanation:
If Rahul age is x, then Sachin age is x-7,
so (x-7)/x = 7/9
=> 9x-63 = 7x
=> 2x = 63
=> x = 31.5
So Sachin age is 31.5 - 7 = 24.5
4. Raju age after 15 years will be 5 times his age 5 years back, What is the present age of Raju
- 15
- 14
- 10
- 8
Answer: Option C
Explanation:
Clearly,
x+15 = 5(x-5)
<=> 4x = 40 => x = 10
5. The total age of A and B is 12 years more than the total age of B and C. C is how many year younger than A
- 11
- 12
- 13
- 14
Answer: Option B
Explanation:
Given that A+B = 12 + B + C
=> A – C = 12 + B – B = 12
=> C is younger than A by 12 years
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