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Question Detail
In how many years Rs 150 will produce the same interest at 8% as Rs. 800 produce in 3 years at 9/2%
- 8
- 9
- 10
- 11
Answer: Option B
Explanation:
Clue:
Firstly we need to calculate the SI with prinical 800,Time 3 years and Rate 9/2%, it will be Rs. 108
Then we can get the Time as
Time = (100*108)/(150*8) = 9
1. Find the rate at Simple interest, at which a sum becomes four times of itself in 15 years.
- 10%
- 20%
- 30%
- 40%
Answer: Option B
Explanation:
Let sum be x and rate be r%
then, (x*r*15)/100 = 3x [important to note here is that simple interest will be 3x not 4x, beause 3x+x = 4x]
=> r = 20%
2. A financier claims to be lending money at simple interest, But he includes the interest every six months for calculating the principal. If he is charging an interest of 10%, the effective rate of interest becomes.
- 10.25%
- 10%
- 9.25%
- 9%
Answer: Option A
Explanation:
Let the sum is 100.
As financier includes interest every six months., then we will calculate SI for 6 months, then again for six months as below:
SI for first Six Months = (100*10*1)/(100*2) = Rs. 5
Important: now sum will become 100+5 = 105
SI for last Six Months = (105*10*1)/(100*2) = Rs. 5.25
So amount at the end of year will be (100+5+5.25)
= 110.25
Effective rate = 110.25 - 100 = 10.25
3. If a sum of money doubles itself in 8 years at simple interest, the ratepercent per annum is
- 12
- 12.5
- 13
- 13.5
Answer: Option B
Explanation:
Let sum = x then Simple Interest = x
Rate = (100 * x) / (x * 8) = 12.5
4. What is the present worth of Rs. 132 due in 2 years at 5% simple interest per annum
- 110
- 120
- 130
- 140
Answer: Option B
Explanation:
Let the present worth be Rs.x
Then,S.I.= Rs.(132 - x)
=› (x*5*2/100) = 132 - x
=› 10x = 13200 - 100x
=› 110x = 13200
x= 120
5. Find the simple interest on Rs 7000 at 50/3 % for 9 months
- Rs. 1075
- Rs. 975
- Rs. 875
- Rs. 775
Answer: Option C
Explanation:
\begin{aligned}
\text{ S.I. = } \frac{P \times R \times T}{100}
\end{aligned}
So, by putting the values in the above formula, our result will be.
\begin{aligned}
\text{ Required result = } \frac{7000 \times 50 \times 9}{3 \times 12 \times 100} = 875
\end{aligned}
[Please note that we have divided by 12 as we converted 9 months in a year format]
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