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Question Detail
Sachin was twice as old as Ajay 10 years back. How old is Ajay today if Sachin will be 40 years old 10 years hence
- 18
- 25
- 15
- 20
Answer: Option D
Explanation:
Sachin's age today = 30 years.
Sachin's age 10 years back = 20 years.
Ajay's age 10 years back = 10 years.
Ajay's age today =20 years
1. A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of this son is
- 21 years
- 22 years
- 23 years
- 24 years
Answer: Option B
Explanation:
Let's Son age is x, then Father age is x+24.
=> 2(x+2) = (x+24+2)
=> 2x+4 = x+26
=> x = 22 years
2. The ages of two persons differ by 16 years. 6 years ago, the elder one was 3 times as old as the younger one. What are their present ages of the elder person
- 15
- 20
- 25
- 30
Answer: Option D
Explanation:
Let's take the present age of the elder person = x
and the present age of the younger person = x – 16
(x – 6) = 3 (x-16-6)
=> x – 6 = 3x – 66
=> 2x = 60
=> x = 60/2 = 30
3. Which of following statements are required to answer the Actual age of Abhinav ?
1. Five years ago, Abhinav's age was double that of his son's age at that time.
2. Present ages of Abhinav and his son are in the ratio of 11 : 6 respectively.
3. Five years hence, the respective ratio of Abhinav age and his son's age will become 12 : 7.
- 1 and 3
- 2 and 3
- Any two of three
- None of three
Answer: Option C
Explanation:
From 2nd we get, Present ages of Abhinav and his son is 11x and 6x,
From 1st we get, Abhinav's present age = 2 * Son's age
From 3rd we get, 5 years hence, Abhinav age / Son's age = 12 / 7
From clearly we can get Abhinav age from any of two equations.
4. Six years ago, the ratio of the ages of Kunal and Sagar was 6:5, Four years hence, the ratio of their ages will be 11:10. What is Sagar age at present
- 10 years
- 12 years
- 14 years
- 16 years
Answer: Option D
Explanation:
Let six years ago the age of Kunal and Sagar are 6x and 5x resp.
then,
\begin{aligned}
=> \frac{(6x+6)+4}{(5x+6)+4} = \frac{11}{10}
\end{aligned}
\begin{aligned}
<=> 10(6x+10) = 11(5x+10)
\end{aligned}
\begin{aligned}
<=> 5x = 10 => x = 2
\end{aligned}
So Sagar age is (5x+6) = 16
5. Tanya's grandfather was 8 times older to her 16 years ago. He would be 3 times of her age 8 years from now. What was ratio of ages of Tanya and her grandfather 8 years ago.
- 11:50
- 11:51
- 11:53
- 11:54
Answer: Option C
Explanation:
Let, Tanya age 16 years ago = x,
Grandfather's age 16 years ago = 8x.
8 years from now, 3(x+16+8) = (8x+16+8)
=> x = 48/5
8 years ago ratio was:
\begin{aligned}
=> \frac{x+8}{8x+8} = \frac{\frac{48}{5}+8}{8 \times \frac{48}{5}+8}
\end{aligned}
\begin{aligned}
=> \frac{88}{424} = \frac{11}{53}
\end{aligned}
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