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The ages of two persons differ by 16 years. 6 years ago, the elder one was 3 times as old as the younger one. What are their present ages of the elder person

  • 15
  • 20
  • 25
  • 30

Answer: Option D

Explanation:

Let's take the present age of the elder person = x
and the present age of the younger person = x – 16
(x – 6) = 3 (x-16-6)
=> x – 6 = 3x – 66
=> 2x = 60
=> x = 60/2 = 30

Similar Questions :

1. A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of this son is

  • 21 years
  • 22 years
  • 23 years
  • 24 years

Answer: Option B

Explanation:

Let's Son age is x, then Father age is x+24.
=> 2(x+2) = (x+24+2)
=> 2x+4 = x+26
=> x = 22 years

2. Total of the ages of A, B ahd C at present is 90 years. Ten years ago, the ratio of their ages was 1: 2: 3. What is the age of B at present

  • 25
  • 30
  • 45
  • 60

Answer: Option B

Explanation:

Let their ages 10 years ago is x, 2x and 3x years.
10 + 2x + 10 + 3x + 10 = 90 hence x= 10
B’s present age = (2x + 10) =30 years

3. The ratio between the present ages of P and Q is 6:7. If Q is 4 years old than P, what will be the ratio of the ages of P and Q after 4 years

  • 7:8
  • 7:9
  • 3:8
  • 5:8

Answer: Option A

Explanation:

Let P age and Q age is 6x years and 7x years.
Then 7x - 6x = 4 <=> x = 4

So required ratio will be (6x+4): (7x+4) => 28:32 => 7:8

4. Raju age after 15 years will be 5 times his age 5 years back, What is the present age of Raju

  • 15
  • 14
  • 10
  • 8

Answer: Option C

Explanation:

Clearly,
x+15 = 5(x-5)
<=> 4x = 40 => x = 10

5. The sum of the present ages of a father and his son is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be

  • 15 years
  • 18 years
  • 20 years
  • 22 years

Answer: Option C

Explanation:

Clue : (60 - x) - 6 = 5(x - 6)

Read more from - Problems on Ages Questions Answers
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