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Question Detail
The distance between two cities A and B is 330 Km. A train starts from A at 8 a.m. and travel towards B at 60 km/hr. Another train starts from B at 9 a.m and travels towards A at 75 Km/hr. At what time do they meet?
- 10 am
- 11 am
- 12 pm
- 1 pm
Answer: Option B
Explanation:
Suppose they meet x hrs after 8 a.m.
then
(Distance moved by first in x hrs) + [Distance moved by second in (x-1) hrs]
= 330
So, 60x+75(x-1) = 330
x=3.
So,they meet at (8+3). i.e 11a.m.
1. A cyclist covers a distance of 750 meter in 2 minutes 30 seconds. What is the speed in km/hr of cyclist
- 16 km/hr
- 17 km/hr
- 18 km/hr
- 19 km/hr
Answer: Option C
Explanation:
\begin{aligned}
Speed = \frac{Distance}{Time} \\
Distance = 750 meter \\
Time = \text{2 min 30 sec} = 150 sec \\
Speed = \frac{750}{150} = 5 m/sec \\
=> 5*\frac{18}{5} km/hr = 18 km/hr
\end{aligned}
2. Ram and Sham are running a race, Ram runs 25% faster than Sham and is able to allow Sham a lead of 7 meters to end a race in dead heat. Find the distance of the race.
- 32 meters
- 35 meters
- 39 meters
- 40.5 meters
Answer: Option B
Explanation:
Important to Note first - Dead Head means - run or finish a race at exactly level or at same time.
From question it is clear that Ram runs faster than Sham by 25%,
So if Sham runs 100 meter in a given time then Ram will run 125 meter in that time.
So if Sham runs 4 meter then Ram will run 5 meter in given time (divide both by 25)
=> Ram can give Sham a lead of 1 meter in 5 meter race to finish race in dead heat.
Ratio of length of start given : length of race :: 1 : 5
As per question, start was given of 7 meter, So,
Length of race was 7 * 5 = 35.
3. 2 trains starting at the same time from 2 stations 200 km apart and going in opposite direction cross each other at a distance of 110 km from one of the stations. What is the ratio of their speeds ?
- 11:9
- 13:9
- 17:9
- 21:9
Answer: Option A
Explanation:
We know total distance is 200 Km
If both trains crossed each other at a distance of 110 km then one train covered 110 km and other 90 km [110+90=200km]
So ratio of their speed = 110:90 = 11:9
4. How many minutes does Aditya take to cover a distance of 400 m, if he runs at a speed of 20 km/hr
- \begin{aligned} 1\frac{1}{5} min\end{aligned}
- \begin{aligned} 2\frac{1}{5} min\end{aligned}
- \begin{aligned} 3\frac{1}{5} min\end{aligned}
- \begin{aligned} 4\frac{1}{5} min\end{aligned}
Answer: Option A
Explanation:
We know that,
\begin{aligned}
Time = \frac{Distance}{Speed} \\
Speed = 20\text{ km/hr} = 20*\frac{5}{18}{ m/sec} \\
= \frac{50}{9}{ m/sec} \\
\text{ Time =} \left(400*\frac{9}{50}\right) \\
= 72 {sec} = 1\frac{1}{5}{ min}
\end{aligned}
5. A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. Find the average speed for first 320 km of tour.
- 70.11 km/hr
- 71.11 km/hr
- 72.11 km/hr
- 73.11 km/hr
Answer: Option B
Explanation:
We know Time = Distance/speed
So total time taken =
\begin{aligned}
\left(\frac{160}{64}+\frac{160}{80}\right) \\
= \frac{9}{2} hours \\
\text{ Time taken for 320 Km = } \\
320*\frac{2}{9} = 71.11 km/hr
\end{aligned}
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