- Home
- Quantitative
- English
- Reasoning
- IT Officer
- Programming
-
Computer
- Computer Awareness Questions Answers - Set 1
- Computer Awareness Questions Answers - Set 2
- Important Abbreviations Computer Awareness Questions Answers
- Important File Extensions Questions Answers
- Computer System Architecture Questions Answers
- MS Office Questions Answers
- MS Excel Questions Answers
- MS PowerPoint Questions Answers
-
GK
- Geography Questions Answers
- Indian History Questions Answers
- World History Questions Answers
- Indian Economy Questions Answers
- Indian Polity and Constitution
- Physics Questions Answers
- Chemistry Questions Answers
- Biology Questions Answers
- First In India
- First In World
- Longest and Largest
- Books and Authors
- Important Days of year
- Countries and Capitals
- Inventions and Inventors
-
Current Affairs
- Current Affairs
- Current Affairs 2018
- Current Affairs 2018 - 2019 PDF
- Current Affairs August 2019
- Current Affairs July 2019
- Current Affairs June 2019
- Current Affairs May 2019
- Current Affairs April 2019
- Current Affairs March 2019
- Current Affairs February 2019
- Current Affairs January 2019
- Current Affairs December 2018
- Current Affairs November 2018
- Current Affairs October 2018
- Current Affairs September 2018
- Govt Jobs
- Exams
- Online Quiz
- You are here
- Home
- Quantitative Aptitude
- Arithmetic Aptitude Questions Answers
- Volume and Surface Area Questions Answers
- Aptitude Question
- Current Affairs 2019
- Current Affairs 2018
- Current Affairs December 2018
- Current Affairs November 2018
- Current Affairs October 2018
- Current Affairs September 2018
- Current Affairs August 2018
- Current Affairs July 2018
- Current Affairs June 2018
- Current Affairs May 2018
- Current Affairs April 2018
- Current Affairs March 2018
- Current Affairs February 2018
- Current Affairs January 2018
- Current Affairs 2018
- Current Affairs PDF
- Current Affairs PDF Download
- Current Affairs July 2019 PDF
- Current Affairs June 2019 PDF
- Current Affairs May 2019 PDF
- Current Affairs April 2019 PDF
- Current Affairs March 2019 PDF
- Current Affairs February 2019 PDF
- Current Affairs January 2019 PDF
- Current Affairs December 2018 PDF
- Current Affairs November 2018 PDF
- Current Affairs October 2018 PDF
- Current Affairs September 2018 PDF
- Current Affairs August 2018 PDF
- Current Affairs July 2018 PDF
- Current Affairs June 2018 PDF
- Current Affairs May 2018 PDF
- Current Affairs April 2018 PDF
- Current Affairs March 2018 PDF
- Current Affairs February 2018 PDF
- Current Affairs January 2018 PDF
Question Detail
Two right circular cylinders of equal volumes have their heights in the ratio 1:2. Find the ratio of their radii.
- \begin{aligned} \sqrt{3}:1 \end{aligned}
- \begin{aligned} \sqrt{7}:1 \end{aligned}
- \begin{aligned} \sqrt{2}:1 \end{aligned}
- \begin{aligned} 2:1 \end{aligned}
Answer: Option C
Explanation:
Let their heights be h and 2h and radii be r and R respectively then.
\begin{aligned}
\pi r^2h = \pi R^2(2h) \\
=> \frac{r^2}{R^2} = \frac{2h}{h} \\
= \frac{2}{1} \\
=> \frac{r}{R} = \frac{\sqrt{2}}{1} \\
=> r:R = \sqrt{2}:1 \\
\end{aligned}
1. There are bricks with 24 cm x 12 cm x 8 cm dimensions. Find the total number of bricks required to construct a wall 24 m long, 8 m high and 60 m thick with 10% of wall filled with mortar.
- 35000
- 40000
- 45000
- 50000
Answer: Option C
Explanation:
So as per question,
\begin{aligned}
\text{Volume of wall} = (2400 * 800 * 60 ) cm^3 \\
\text{Volume of bricks} = \text { 90% of volume of wall } \\
= [ \frac{90}{100} * 2400 * 800 * 60 ] cm^3 \\
\text{ Volume of 1 brick = } (24 * 12 * 8) cm^3 \\
\text{Number of Bricks required} \\
= \frac{ (\frac{90}{100}) * (2400 * 800 * 60)}{24 * 12 * 8} \\
= 45000
\end{aligned}
2. A swimming pool 9 m wide and 12 m long is 1 m deep on the shallow side and 4 m deep on the deeper side. Its volume is:
- 260
- 262
- 270
- 272
Answer: Option C
Explanation:
Volume will be length * breadth * height, but in this case two heights are given so we will take average,
\begin{aligned}
Volume = \left(12*9*\left(\frac{1+4}{2}\right)\right)m^3 \\
12*9*2.5 m^3 = 270 m^3
\end{aligned}
3. Find the surface area of a 10cm*4cm*3cm brick.
- 154 cm square
- 156 cm square
- 160 cm square
- 164 cm square
Answer: Option D
Explanation:
Surface area of a cuboid = 2(lb+bh+hl) cm square
So,
Surface area of a brick = 2(10*4+4*3+3*10) cm square
= 2(82) cm square = 164 cm square
4. A hemisphere and a cone have equal bases. If their heights are also equal, then the ratio of their curved surface will be :
- \begin{aligned} 2:1 \end{aligned}
- \begin{aligned} 1:\sqrt{2} \end{aligned}
- \begin{aligned} \sqrt{2}:1 \end{aligned}
- \begin{aligned} \sqrt{3}:1 \end{aligned}
Answer: Option C
Explanation:
Let the radius of hemisphere and cone be R,
Height of hemisphere H = R.
So the height of the cone = height of the hemisphere = R
Slant height of the cone
\begin{aligned}
= \sqrt{R^2+R^2} \\
= \sqrt{2}R \\
\frac{\text{Hemisphere Curved surface area}}{\text{Cone Curved surface area}} = \\
\frac{2\pi R^2}{\pi *R*\sqrt{2}R} \\
= \sqrt{2}:1
\end{aligned}
5. The slant height of a conical mountain is 2.5 km and the area of its base is 1.54 km square. The height of mountain is :
- 2.3 km
- 2.4 km
- 2.5 km
- 2.6 km
Answer: Option B
Explanation:
Let the radius of the base be r km. Then,
\begin{aligned}
\pi r^2 = 1.54 \\
r^2 = \frac{1.54*7}{22} = 0.49\\
= 0.7 km \\
\text{Now l=2.5 km, r = 0.7 km} \\
h = \sqrt{2.5^2 - 0.7^2} km \\
=\sqrt{6.25 - 0.49}\\
=\sqrt{5.76} km \\
= 2.4 km
\end{aligned}
Thanks ! Your comment will be approved shortly !
- Copyright 2014 - All rights reserved
- Terms Of Use & Privacy Policy
- Contact Us
- Copyright