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Question Detail
Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is ?
- 40 meter
- 45 meter
- 50 meter
- 55 meter
Answer: Option C
Explanation:
Let the length of each train is x meter
Distance will be x+x = 2x
Relative Speed = 46-36 = 10 km/hr
= 10*(5/18) = 25/9 m/sec
Distance = Speed*Time
\begin{aligned}
2x = \frac{25}{9}*36 \\
2x = 100 \\
=> x = 50
\end{aligned}
So length of both the trains are 50 meters
1. A train is 360 meter long is running at a speed of 45 km/hour. In what time will it pass a bridge of 140 meter length.
- 20 seconds
- 30 seconds
- 40 seconds
- 50 seconds
Answer: Option C
Explanation:
Speed = 45 Km/hr = 45*(5/18) m/sec
= 25/2 m/sec
Total distance = 360+140 = 500 meter
Time = Distance/speed
\begin{aligned}
= 500*\frac{2}{25} = 40 seconds
\end{aligned}
2. A train, 800 meter long is running with a speed of 78 km/hr. It crosses a tunnel in 1 minute. What is the length of the tunnel ?
- 650 meter
- 555 meter
- 500 meter
- 458 meter
Answer: Option C
Explanation:
Let length of tunnel is x meter
Distance = 800+x meter
Time = 1 minute = 60 seconds
Speed = 78 km/hr = 78*5/18 m/s = 65/3 m/s
Distance = Speed*Time
\begin{aligned}
=> 800+x = \frac{65}{3}*60 \\
=> 800+x = 20*65 = 1300 \\
=> x = 1300 - 800 = 500 \\
\end{aligned}
So the length of the tunnel is 500 meters.
[If you want to calculate it practically, then please have your copy and pen and take a ride of Kalka to Shimla toy train in north India. It has many tunnels on the way :) ]
3. A train is running with a speed of 60 kmph and its length is 110 metres. Calculate the time by which it will pass a man running opposite with speed of 6 kmph.
- 2 second
- 4 second
- 6 second
- 8 second
Answer: Option C
Explanation:
From the given question,
we will first calculate the speed of train relative to man,
=> ( 60 + 6 ) = 66 km/hr ( we added 6 because man is running opposite )
Convert it in metre/second
\begin{aligned}
= 66 \times\frac{5}{18} \\
= \frac{55}{3} m/sec\\
\text{Time it will take to pass man }\\
= 110 \times \frac{3}{55} \\
= 6 \text{ seconds}
\end{aligned}
4. In what time will a train 100 meters long cross an electric pole, if its speed is 144 km/hr
- 5 seconds
- 4.5 seconds
- 3 seconds
- 2.5 seconds
Answer: Option D
Explanation:
First convert speed into m/sec
Speed = 144*(5/18) = 40 m/sec
Time = Distance/speed
= 100/40 = 2.5 seconds
5. A train speeds past a pole in 15 seconds and a platform 100 meter long in 25 seconds. What is length of the train ?
- 140 meter
- 145 meter
- 150 meter
- 155 meter
Answer: Option C
Explanation:
Let the length of the train is x meter and Speed of the train is y meter/second
Then x/y = 15 [because distance/speed = time]
=> y = 15/x
\begin{aligned}
=> \frac{x+100}{25} = \frac{x}{15} \\
x = 150 \text{ meters}
\end{aligned}
So length of the train is 150 meters
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