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Question Detail
1/2 is what percent of 1/3
- 150%
- 200%
- 250%
- 300%
Answer: Option A
Explanation:
1/2/1/3 * 100 = 1/2 * 3/1 * 100 = 150 %
1. A housewife saved Rs. 2.50 in buying an item on sale. If she spent Rs. 25 for the item, approximately how much percent she saved in the transaction
- 9%
- 10%
- 11%
- 12%
Answer: Option A
Explanation:
Actual Price = Rs.25 + Rs.2.50 = Rs.27.5
Saving = Rs.2.5
\begin{aligned}\text{Percentage Saving = }\dfrac{2.5}{27.5}\times 100 \\
= \dfrac{250}{27.5} = \dfrac{2500}{275}\\
= \dfrac{100}{11} = 9\dfrac{1}{11}\% \approx 9\%\end{aligned}
2. 2 is what percent of 50
- 2%
- 4%
- 6%
- 8%
Answer: Option B
Explanation:
2/50 * 100 = 1/25 * 100 = 4 %
3. If sales tax is reduced from 5% to 4%, then what difference it will make if you purchase an item of Rs. 1000
- 10
- 20
- 30
- 40
Answer: Option A
Explanation:
Clue: Answer will be 5% of 1000 - 4% of 1000
4. Total number of boys and girls in a school is 150. If the number of boys is x, then girls become x% of the total number of students. The number of boys is
- 50
- 60
- 70
- 80
Answer: Option B
Explanation:
Clearly,
x% of 150 = 150 - x [as x is number of boys]
\begin{aligned}
=> x + \frac{x}{100} * 150 = 150 \\
=> \frac{5}{2}x = 150 \\
=> x = 60 \\
\end{aligned}
5. In a hotel, 60% had vegetarian lunch while 30% had non-vegetarian lunch and 15% had both type of lunch. If 96 people were present, how many did not eat either type of lunch ?
- 27
- 26
- 25
- 24
Answer: Option D
Explanation:
\begin{aligned}
n(A) = \left(\frac{60}{100}*96\right) = \frac{288}{5} \\
n(B) = \left(\frac{30}{100}*96\right) = \frac{144}{5} \\
n(A\cap B) = \left(\frac{15}{100}*96\right) = \frac{72}{5} \\
\text{People who have either or both lunch} \\
n(A\cup B) = \frac{288}{5}+\frac{144}{5}-\frac{72}{5} \\
= \frac{360}{5} = 72
\end{aligned}
So People who do no have either lunch were = 96 -72
= 24
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