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Question Detail
In a throw of dice what is the probability of getting number greater than 5
- 1/2
- 1/3
- 1/5
- 1/6
Answer: Option D
Explanation:
Number greater than 5 is 6, so only 1 number
Total cases of dice = [1,2,3,4,5,6]
So probability = 1/6
1. In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither blue nor green?
- 2/3
- 8/21
- 3/7
- 9/22
Answer: Option B
Explanation:
Total number of balls = (8 + 7 + 6) = 21
Let E = event that the ball drawn is neither blue nor green =e vent that the ball drawn is red.
Therefore, n(E) = 8.
P(E) = 8/21.
2. Two unbiased coins are tossed. What is probability of getting at most one tail ?
- \begin{aligned} \frac{1}{2} \end{aligned}
- \begin{aligned} \frac{1}{3} \end{aligned}
- \begin{aligned} \frac{3}{2} \end{aligned}
- \begin{aligned} \frac{3}{4} \end{aligned}
Answer: Option D
Explanation:
Total 4 cases = [HH, TT, TH, HT]
Favourable cases = [HH, TH, HT]
Please note we need atmost one tail, not atleast one tail.
So probability = 3/4
3. In a throw of coin what is the probability of getting head.
- 1
- 2
- 1/2
- 0
Answer: Option C
Explanation:
Total cases = [H,T] - 2
Favourable cases = [H] -1
So probability of getting head = 1/2
4. From a pack of 52 cards, two cards are drawn together, what is the probability that both the cards are kings
- 2/121
- 2/221
- 1/221
- 1/13
Answer: Option C
Explanation:
\begin{aligned}
\text{Total cases =} ^{52}C_2 \\
= \frac{52*51}{2*1} = 1326 \\
\text{Total King cases =} ^{4}C_2 \\
= \frac{4*3}{2*1} = 6 \\
\text{Probability =} = \frac{6}{1326}\\
= \frac{1}{221} \\
\end{aligned}
5. Three unbiased coins are tossed, what is the probability of getting at least 2 tails ?
- 1/3
- 1/6
- 1/2
- 1/8
Answer: Option C
Explanation:
Total cases are = 2*2*2 = 8, which are as follows
[TTT, HHH, TTH, THT, HTT, THH, HTH, HHT]
Favoured cases are = [TTH, THT, HTT, TTT] = 4
So required probability = 4/8 = 1/2
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