# Probability Questions Answers

• #### 1. In a throw of coin what is the probability of getting head.

1. 1
2. 2
3. 1/2
4. 0
##### Answer And Explanation

Answer: Option C

Explanation:

Total cases = [H,T] - 2
Favourable cases = [H] -1
So probability of getting head = 1/2

• #### 2. In a throw of coin what is the probability of getting tails.

1. 1
2. 2
3. 1/2
4. 0
##### Answer And Explanation

Answer: Option C

Explanation:

Total cases = [H,T] - 2
Favourable cases = [T] -1
So probability of getting tails = 1/2

• #### 3. Two unbiased coins are tossed. What is probability of getting at most one tail ?

1. \begin{aligned} \frac{1}{2} \end{aligned}
2. \begin{aligned} \frac{1}{3} \end{aligned}
3. \begin{aligned} \frac{3}{2} \end{aligned}
4. \begin{aligned} \frac{3}{4} \end{aligned}
##### Answer And Explanation

Answer: Option D

Explanation:

Total 4 cases = [HH, TT, TH, HT]
Favourable cases = [HH, TH, HT]
Please note we need atmost one tail, not atleast one tail.

So probability = 3/4

• #### 4. Three unbiased coins are tossed, what is the probability of getting at least 2 tails ?

1. 1/3
2. 1/6
3. 1/2
4. 1/8
##### Answer And Explanation

Answer: Option C

Explanation:

Total cases are = 2*2*2 = 8, which are as follows
[TTT, HHH, TTH, THT, HTT, THH, HTH, HHT]

Favoured cases are = [TTH, THT, HTT, TTT] = 4

So required probability = 4/8 = 1/2

• #### 5. In a throw of dice what is the probability of getting number greater than 5

1. 1/2
2. 1/3
3. 1/5
4. 1/6
##### Answer And Explanation

Answer: Option D

Explanation:

Number greater than 5 is 6, so only 1 number
Total cases of dice = [1,2,3,4,5,6]

So probability = 1/6

• #### 6. What is the probability of getting a sum 9 from two throws of dice.

1. 1/3
2. 1/9
3. 1/12
4. 2/9
##### Answer And Explanation

Answer: Option B

Explanation:

Total number of cases = 6*6 = 36

Favoured cases = [(3,6), (4,5), (6,3), (5,4)] = 4

So probability = 4/36 = 1/9

• #### 7. Two dice are thrown simultaneously. What is the probability of getting two numbers whose product is even ?

1. 3/4
2. 1/4
3. 7/4
4. 1/2
##### Answer And Explanation

Answer: Option A

Explanation:

Total number of cases = 6*6 = 36

Favourable cases = [(1,2),(1,4),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,2),(3,4),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,2),(5,4),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)] = 27

So Probability = 27/36 = 3/4

Post a comment

• #### rushikesh 2 years ago

The probability of getting 9 cards of the same suit in one hand at a game of bridge

• #### Aaradhy 4 years ago

Ty for this questions but if there should be more que then it would be more good????????????????

• #### Taimoor khan 4 years ago

Excellent, fabulous ... but
Add more questions plz

• #### Preeta Shashi 4 years ago

there are 12 face cards and not 16 as given in solution of one of the question.

• #### vijay 4 years ago

really helpful....in less time preparation...

#### mastguru 4 years ago replied

Glad to know that Vijay !

#### mastguru 4 years ago replied

Thanks Taimoor for your kind feedback

#### mastguru 4 years ago replied

Sure Aaradhy we are working on it. thanks for your feedback !

• #### aog 6 years ago

Thanks and God bless you for these questions

#### mastguru 6 years ago replied

Thanks AOG !!!

• #### juma 6 years ago

Thankx for help us

#### mastguru 6 years ago replied

Welcome Juma !

• #### shalu 7 years ago

ques are gud.....bt add up more ques....

• #### ranga 7 years ago

more questions please

• #### Master Sridhar 7 years ago

Hello Boss, Post questions for IBPS SO

• #### abhi 8 years ago

more questions plz

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