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Question Detail
Three unbiased coins are tossed, what is the probability of getting at least 2 tails ?
- 1/3
- 1/6
- 1/2
- 1/8
Answer: Option C
Explanation:
Total cases are = 2*2*2 = 8, which are as follows
[TTT, HHH, TTH, THT, HTT, THH, HTH, HHT]
Favoured cases are = [TTH, THT, HTT, TTT] = 4
So required probability = 4/8 = 1/2
1. Two dice are thrown simultaneously. What is the probability of getting two numbers whose product is even ?
- 3/4
- 1/4
- 7/4
- 1/2
Answer: Option A
Explanation:
Total number of cases = 6*6 = 36
Favourable cases = [(1,2),(1,4),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,2),(3,4),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,2),(5,4),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)] = 27
So Probability = 27/36 = 3/4
2. From a pack of 52 cards, two cards are drawn together, what is the probability that both the cards are kings
- 2/121
- 2/221
- 1/221
- 1/13
Answer: Option C
Explanation:
\begin{aligned}
\text{Total cases =} ^{52}C_2 \\
= \frac{52*51}{2*1} = 1326 \\
\text{Total King cases =} ^{4}C_2 \\
= \frac{4*3}{2*1} = 6 \\
\text{Probability =} = \frac{6}{1326}\\
= \frac{1}{221} \\
\end{aligned}
3. From a pack of 52 cards, 1 card is drawn at random. Find the probability of a face card drawn.
- 3/13
- 1/52
- 1/4
- None of above
Answer: Option A
Explanation:
Total number of cases = 52
Total face cards = 12 [favourable cases]
So probability = 12 /52 = 3/13
4. Bag contain 10 back and 20 white balls, One ball is drawn at random. What is the probability that ball is white
- 1
- 2/3
- 1/3
- 4/3
Answer: Option B
Explanation:
Total cases = 10 + 20 = 30
Favourable cases = 20
So probability = 20/30 = 2/3
5. In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither blue nor green?
- 2/3
- 8/21
- 3/7
- 9/22
Answer: Option B
Explanation:
Total number of balls = (8 + 7 + 6) = 21
Let E = event that the ball drawn is neither blue nor green =e vent that the ball drawn is red.
Therefore, n(E) = 8.
P(E) = 8/21.
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