2020-01-06, 16:42 | #23 |
Oct 2019
2 Posts |
Hello, first.
This text was written with the help of google translator. I am entering this world of factoring, 6 months ago. I have problems factoring a number of 1024 bits, I know it is too large. So about polyselect, it ran for 99 days. tasks.polyselect.P = 10000000 tasks.polyselect.admax = 1e8 tasks.polyselect.adrange = 250 tasks.polyselect.degree = 6 tasks.polyselect.incr = 60 tasks.polyselect.nq = 1296 tasks.polyselect.nrkeep = 100 tasks.polyselect.threads = 2 n: 1024 bits skew: 3280536.395 # MurphyE (Bf = 1.43e + 09, Bg = 7.00e + 08, area = 3.07e + 18) = 4.29e-16 Is this result good? What about sieve, tasks.sieve.mfb0 = 70 tasks.sieve.mfb1 = 105 tasks.sieve.ncurves0 = 30 tasks.sieve.ncurves1 = 30 tasks.sieve.qrange = 1000 tasks.sieve.las.threads = 4 tasks.I = 16 Hundreds of found 0. Info: Lattice Sieving: Found 0 relations in '', total is now 102/3794906671 |
2020-01-06, 21:34 | #24 |
"Curtis"
Feb 2005
Riverside, CA
2·11·227 Posts |
The MurphyE score depends on other parameters that you didn't list. You also didn't list the polynomial, so I can't evaluate its quality myself.
You didn't list the large-prime bound parameters, nor lim0 and lim1, so I can't tell you how good or bad your param choices are. I'd change I=16 to I=17, for a start. If you know it is too large, why are you trying to factor it? Your machine isn't capable of finishing the job. EDIT: Sorry, I had in mind a 768-bit number, not 1024-bit. When the CADO group solved RSA768, they spent about 20 core-years on poly select. You spent 1 core-year (100 days * 4 cores, as a guess). So, you're about 5% of the way to "enough" for a number 1/1000th the difficulty of the one you're trying to factor. So, a mere 500000 more core-days of poly select should be about right. Then, the sieving might take 20-30x that long, depending on how good your parameter choice is. Your parameters are in the ballpark of decent for a 768-bit number, though. Last fiddled with by VBCurtis on 2020-01-06 at 21:58 |
2020-01-07, 00:09 | #25 |
Oct 2019
2 Posts |
Thanks for the answer. The complementary data:POLY: Code:
skew: 3280536.395 c0: -2963521726450804168545574989181604944974055470262264097100 c1: -8152690578728840862728149245184473131571416030581953 c2: 4530419292332128770249146516543999988943765890 c3: 87634441208849856388603554546291847879 c4: -844120661985043880048339652132070 c5: 13409199100611061897507722 c6: -59711977080 Y0: -108073099124290591101496444923166525774281367655542 Y1: 2355770915946536318263 # MurphyE (Bf=1.43e+09,Bg=7.00e+08,area=3.07e+18) = 4.29e-16 # f(x) = -59711977080*x^6+13409199100611061897507722*x^5-844120661985043880048339652132070*x^4+87634441208849856388603554546291847879*x^3+4530419292332128770249146516543999988943765890*x^2-8152690578728840862728149245184473131571416030581953*x-2963521726450804168545574989181604944974055470262264097100 # g(x) = 2355770915946536318263*x-108073099124290591101496444923166525774281367655542 Param: lim0 = 700000000 lim1 = 1430000000 lpb0 = 35 lpb1 = 36 maxfailed = 5000 name = c310 tasks.I = 16 tasks.maxtimedout = 3000 tasks.qmin = 1073741823 tasks.threads = 2 tasks.wutimeout = 24000 tasks.filter.maxlevel = 40 tasks.filter.target_density = 170.0 tasks.filter.purge.keep = 160 tasks.linalg.m = 64 tasks.linalg.n = 64 tasks.linalg.bwc.interleaving = 0 tasks.linalg.bwc.interval = 1000 tasks.linalg.characters.nchar = 50 tasks.polyselect.P = 10000000 tasks.polyselect.admax = 1e6 tasks.polyselect.adrange = 1000 tasks.polyselect.degree = 6 tasks.polyselect.incr = 60 tasks.polyselect.nq = 1296 tasks.polyselect.nrkeep = 100 tasks.polyselect.threads = 2 tasks.sieve.mfb0 = 70 tasks.sieve.mfb1 = 105 tasks.sieve.ncurves0 = 30 tasks.sieve.ncurves1 = 30 tasks.sieve.qrange = 1000 tasks.sieve.las.threads = 4 tasks.polyselect.P = 20000000 tasks.polyselect.admax = 2e12 tasks.polyselect.adrange = 10000000 tasks.polyselect.incr = 110880 tasks.polyselect.nq = 1296 # this is 6^4 tasks.polyselect.nrkeep = 100 tasks.wutimeout = 7200 tasks.polyselect.sopteffort = 20 tasks.polyselect.ropteffort = 10 Read and your post, https://mersenneforum.org/showpost.p...81&postcount=6 "I bet they'd have better-yet performance with nq of 7776 and admax around 3e11" Last fiddled with by VBCurtis on 2020-01-07 at 01:43 Reason: added code tags |
2020-01-07, 01:57 | #26 |
"Curtis"
Feb 2005
Riverside, CA
2·11·227 Posts |
You're missing the point entirely- you have copied / used parameters from either RSA768 (a 232-digit number) or RSA-240. These are, you know, SIXTY or more digits smaller than the number you wish to factor.
If you tried to use good parameters from a 180-digit job to factor a 240-digit job, they would fail miserably. So will yours, for the same reasons. 1. You're not getting any relations because the siever is too small. You need I=18 for a kilobit number. One instance of this siever requires 120GB or more of memory. 2. You don't know what you are doing, so you don't know how to scale any of these settings for this job. Since this job is impossible for you to complete, this doesn't matter a whole lot; but if you happen to be pals with Ben Delo and share his level of hardware resources, you would factor a 140 digit number, then 160, then 180, then 200, then 220 and see how the settings change and memory needs change and time requirements change. Then you and Ben would realize 1024-bit GNFS is not a good idea, but maybe 250-digit GNFS is possible (it is). 3. There are discussions scattered around about trying to factor RSA-1024. You should find these papers or forum posts for ideas about how big a job this is, and what settings might be reasonable. Things like 4 large primes on one side & 3 on the other, 42-bit large primes (or 43, or 44- how much disk space do you have?). Once you have 20 or 50 TB of disk prepared for this task, then you can decide how to write a grant proposal to get access to a cluster with, say, 512GB of memory per node to attempt the postprocessing. That matrix might have a billion rows and a billion columns. In closing, your settings *might* factor a 230-digit number in some reasonable number of decades, but they won't factor a kilobit number before you die. EDIT: I pasted your poly into cownoise to see what its score was. Results: optimal skew 8832525.55458 score 7.74032539e-22 Last fiddled with by VBCurtis on 2020-01-07 at 02:16 |
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