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Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are

  • 42,30
  • 42,31
  • 42,32
  • 42,33

Answer: Option D

Explanation:

Let their marks be (x+9) and x.
Then, x+9 = 56/100(x + 9 +x)
=> 25(x+9)
=> 14 (2x + 9)
=> 3x = 99
=> x = 33.
So, their marks are 42 and 33

Similar Questions :

1. Three candidates contested an election and received 1136, 7636 and 11628 votes respectively. What percentage of the total votes did the winning candidate got

  • 55%
  • 56%
  • 57%
  • 58%

Answer: Option C

Explanation:

Total number of votes polled = (1136 + 7636 + 11628) = 20400

So, Required percentage = 11628/20400 * 100 = 57%

2. 2 is what percent of 50

  • 2%
  • 4%
  • 6%
  • 8%

Answer: Option B

Explanation:

2/50 * 100 = 1/25 * 100 = 4 %

3. What is 15 percent of 34

  • 5.10
  • 4.10
  • 3.10
  • 2.10

Answer: Option A

Explanation:

It will be 15% of 34
= (15/100) * 34 = 5.10

4. What will be the fraction of 20%

  • 1/4
  • 1/5
  • 1/10
  • None of above

Answer: Option B

Explanation:

It will 20*1/100 = 1/5

5. If sales tax is reduced from 5% to 4%, then what difference it will make if you purchase an item of Rs. 1000

  • 10
  • 20
  • 30
  • 40

Answer: Option A

Explanation:

Clue: Answer will be 5% of 1000 - 4% of 1000

Read more from - Percentage Questions Answers
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