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Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are

  • 42,30
  • 42,31
  • 42,32
  • 42,33

Answer: Option D

Explanation:

Let their marks be (x+9) and x.
Then, x+9 = 56/100(x + 9 +x)
=> 25(x+9)
=> 14 (2x + 9)
=> 3x = 99
=> x = 33.
So, their marks are 42 and 33

Similar Questions :

1. A student multiplied a number by 3/5 instead of 5/3. What is the percentage error.

  • 64%
  • 65%
  • 66%
  • 67%

Answer: Option A

Explanation:

Let the number be x,
then,
53−35=1615x



Error% = (1615x∗35∗100)

2. 2 is what percent of 50

  • 2%
  • 4%
  • 6%
  • 8%

Answer: Option B

Explanation:

2/50 * 100 = 1/25 * 100 = 4 %

3. 2.09 can be expressed in terms of percentage as

  • 2.09%
  • 20.9%
  • 209%
  • 0.209%

Answer: Option C

Explanation:

While calculation in terms of percentage we need to multiply by 100, so
2.09 * 100 = 209.

4. Three candidates contested an election and received 1136, 7636 and 11628 votes respectively. What percentage of the total votes did the winning candidate got

  • 55%
  • 56%
  • 57%
  • 58%

Answer: Option C

Explanation:

Total number of votes polled = (1136 + 7636 + 11628) = 20400

So, Required percentage = 11628/20400 * 100 = 57%

5. 88% of 370 + 24% of 210 - x = 118

  • 150
  • 250
  • 158
  • 258

Answer: Option D

Read more from - Percentage Questions Answers
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